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Zepler [3.9K]
3 years ago
7

USE THE DISTANCE FORMULA TO FIND THE DISTANCE BETWEEN THE TWO POINTS. (1,-9) AND (6,-6).

Mathematics
1 answer:
harina [27]3 years ago
8 0

Answer:

5.8

or

5.830952

Step-by-step explanation:

Using distance formula

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Simplify each expression<br>4sg/-5g<br>and<br>(8 + 7a) + 4
Yanka [14]

\dfrac{4sg}{-5g}=-\dfrac{4}{5}\cdor\dfrac{sg}{g}=-\dfrac{4}{5}s\\\\(8+7a)+4=7a+(8+4)=7a+12

5 0
3 years ago
What is the inverse and restricted domain of the equation 8x^2-3
kari74 [83]

Answer:  \bold{y=\pm \dfrac{\sqrt{2(x+3)}}{4},\qquad x\neq -3}

<u>Step-by-step explanation:</u>

y = 8x² - 3            (Restriction: none -  x is All Real Numbers)

The inverse is when you swap the x's and y's and then solve for y

x = 8y² - 3            <em>swapped the x and y</em>

x + 3 = 8y²           <em>added 3 to both sides</em>

\dfrac{x+3}{8}=y^2           <em>divided both sides by 8</em>

\sqrt{\dfrac{x+3}{8}}=\sqrt{y^2}           <em>square rooted both sides</em>

\pm \sqrt{\dfrac{x+3}{8}}=y           <em>simplified</em>

\pm \sqrt{\dfrac{x+3}{8}\bigg(\dfrac{2}{2}\bigg)}=y           rationalized the denominator

\pm \sqrt{\dfrac{2(x+3)}{16}}=y           <em>simplified</em>

\pm \dfrac{\sqrt{2(x+3)}}{4}=y           <em>simplified</em>

<u>Restriction:</u>

The radical <em>(inside the square root sign)</em> cannot be negative

→  2(x + 3) ≥ 0

      x + 3 ≥ 0         <em>divided both sides by 2</em>

      x       ≥ -3         <em>subtracted 3 from both sides</em>



4 0
3 years ago
Unit test<br> Evaluate the following expression.<br> Sum<br> 2+1x2<br> ng de<br> racting
DIA [1.3K]

Answer:

  • 2+7∛³≡34543.8947924

Step-by-step explanation:

3 0
3 years ago
How do you write 58.8 an Expanded Form and Word Form? PLEASE HELP ME
stepan [7]

(5 x 10) + (8 x 1) + (8 x 0.1)

OR

50 + 8 + .8

Fifty-eight and eight tenths

Hope this helped!

4 0
4 years ago
Read 2 more answers
Please Answer ASAP! Will give Brainliest to person who is fast and right! Thxx
andrew11 [14]

Answer: AE = 120.83 m  DE= 148.66 m

The perimeter of the pentagon is 699.49

Sketch attached.

Step-by-step explanation: First we have to imagine the shape of the pentagon. In order to satisfy the requirement  "that E is 50 m from the side AB and 30 m from the side BC," <em><u>this must be a concave pentagon. </u></em>

To determine the lengths of sides AE and DE, subtract the given distances of E from the lines, and use those values in the Pythagorean Theorem.

AE: 110^{2}+50^{2}=14600     \sqrt{14600}=120.8304597

DE: 100^{2}+110^{2}=22100   \sqrt{22100}=148.6606875

Add those lengths and the remaining sides of the "rectangle shown below" to calculate the perimeter.

280+150+120.83+148.66= 699.49

3 0
3 years ago
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