1. Simplifying ∛54 gives 3∛2
2. 27^1/3 * (27)^3 is equal to 27
3. The expression (2j4k)^4/5 can be written as ![\sqrt[4]{32j^{20}k^{5} }^{5}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B32j%5E%7B20%7Dk%5E%7B5%7D%20%20%7D%5E%7B5%7D)
making the first option the correct option
4. simplifying ![\sqrt[4]{16x^{4} y^{12} }](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16x%5E%7B4%7D%20y%5E%7B12%7D%20%7D)
will result to 2x∛y
5. simplifying ![\sqrt[5]{2940x^{13} y^{7} }](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2940x%5E%7B13%7D%20y%5E%7B7%7D%20%7D)
will result to 
making the last option the correct option
<h3>How to simplify
</h3>
<u>given data</u>
= ( 2940 * x^13 * y^7 )^1/5
multiplying the values inside the parenthesis by ^1/2
we can therefore say that the last option is the answer
Read more on equations here: brainly.com/question/22688504
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Answer:
11.333333333333 (repeated)
Step-by-step explanation:
1.5 and 10 are like terms, so you need to put them together and keep x on one side by itself. This means that you need to subtract 1.5. The new equation will be .75x = 8.5. Then, you divide by .75. This will then give you the final result, x = 11.3 repeated
Answer:
0.0
Step-by-step explanation:
The theorem does not apply.
1. Set the function f(x)=sqrt(x-1) equal to 0 to find what values of x make f(x) defined. So:
x - 1 is < or = to 0
x > or = to 0
2.) find the values where x is defined:
x - 1 > or = to 0
x > or = to 0
Domain = all values of x that define f(x)
[1,infinity)
{x|x> or = to 1}
DNE because 1 is not in the domain because (1-1)^1/2 = 0.
Answer:
$8.6
Step-by-step explanation:
The total tax is 8 dollars and 60 cents
