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3 years ago

Find x and y in the following figure

Mathematics

1 answer:

Ipatiy [6.2K]3 years ago

6 0

Y=145, I’m not sure about X

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What is 2 3/10 as a percent?

kobusy [5.1K]

2 3/10 = 2.3
To get this number as a percent, we need to multiply it by 100: 2.3 is a whole number, and can be represented by fraction 2.3/1
A percentage is represented by a fraction over 100. So to transform 2.3/1 to a percentage, just multiply both numerator and denominator by 100, and you'll get 230/100.
So 2 3/10 is 230% as a percent.

Hope this Helps! :)

4 0

3 years ago

Read 2 more answers

Please answer asap it’s due in 1 min procrastination

Ipatiy [6.2K]

Answer:

r=ts/-qu

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is the length of BC? Round to the nearest tenth.

Kay [80]

Answer:

BC ≈ 14.5 cm

Step-by-step explanation:

Using the sine ratio in the right triangle

sin65° = $\frac{opposite}{hypotenuse}$ = $\frac{BC}{AB}$ = $\frac{BC}{16}$ ( multiply both sides by 16 )

16 × sin65° = BC , then

BC ≈ 14.5 cm ( to the nearest tenth )

6 0

3 years ago

PLEASE EXPLAIN TOO SO I CAN SOLVE OTHER SIMILAR ONES.

jeka57 [31]

Answer: x = 30' , y = 45'

hope this helps

Step-by-step explanation:

U is 90' it's a right triangle

well simple VRT you already know 2 angles which is 60' and 90'

R = 60'

V = 90'

T = x

you know that a triangle = 180'

so you do

180 - 60 - 90 = x

30 = x

if you want to do y

then you already know that U is 90' on both sides.

since you also know S,

S = 45'

U = 90'

V = y

180 - 90 - 45 = y

45 = y

4 0

3 years ago

On a 8.5 x 11 inches (or larger) paper, create a carnival game (for example it could be: throwing a dart at a target, ball throu

Keith_Richards [23]

The probability of winning the game is 0.065

<h3>The description of the game</h3>

The game involves throwing two darts at two targets.

To win the game, the darts must hit anywhere in the following shapes

Rectangle: 5 by 4 inches
Circle: Radius, r = 3 inches

<h3>The probability of winning</h3>

The area of the paper is:

Area = 8.5 inches * 11 inches

Area = 93.5 square inches

The area of the rectangle on the paper is:

Area = 5 inches * 4 inches

Area = 20 square inches

The area of the circle on the paper is:

Area = π * (3 inches)²

Area = 28.3 square inches

The probability of landing on both shapes is

P(Both) = 20/93.5 * 28.3/93.5

Evaluate

P(Both) = 0.065

Hence, the probability of winning the game is 0.065