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3 years ago

If 180 kg of sugar is to be divided into 3 quantities of ratio 2:3:4 find the smallest and largest quantities.

Mathematics

2 answers:

steposvetlana [31]3 years ago

4 0

Answer:

smallest amount of sugar = 40 kg

largest amount of sugar = 80 kg

Step-by-step explanation:

2 : 3 : 4

2 + 3 + 4 = 9

180 ÷ 9 = 20

Therefore,

2 : 3 : 4 = (2 x 20) : (3 x 20) : (4 x 20) = 40 : 60 : 80

So the smallest amount of sugar = 40 kg

and the largest amount of sugar = 80 kg

uranmaximum [27]3 years ago

3 0

Ratios be 2x ,3x,4x

$\\ \tt\hookrightarrow 2x+3x+4x=180$

$\\ \tt\hookrightarrow 9x=180$

$\\ \tt\hookrightarrow x=20$

2x=40
4x=80

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If 180 kg of sugar is to be divided into 3 quantities of ratio 2:3:4 find the smallest and largest quantities.​

If 180 kg of sugar is to be divided into 3 quantities of ratio 2:3:4 find the smallest and largest quantities.