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Elza [17]
3 years ago
15

Which reaction is a decomposition reaction? A. 2KClO3 → 2KCl + 3O2 B. 4Na + O2 → 2Na2O C. ZnS + 3O2 → 2ZnO + 2SO2 D. 2NaBr + CaF

2 → 2NaF + CaBr2
Chemistry
1 answer:
ivann1987 [24]3 years ago
8 0

Answer:

  • A. 2KClO₃ → 2KCl + 3O₂

Explanation:

In a decompostion reaction one single substances decomposes into two or more substances.

The general form for a decompostion reaction is: AB → A + B

In the reaction 2KClO₃ → 2KCl + 3O₂, the reactant, which is the compound shown on the left side of the reaction, i.e. KClO₃ will disappear and two new substances, the products, shown on the right side of the equation, will appear.

So, it is said that KClO₃ decomposes into KCl and O₂.

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Some of the most dangerous conditions occur when temperatures are hovering around _______ degrees fahrenheit, or freezing, when
Olin [163]

Answer:

32 ° F

Explanation:

Freezing temp for water is 32 degrees at 1 atm

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2 years ago
Materials with_____ bonds tend to be more easily scratched
iren [92.7K]

Materials with ionic bonds tend to be more easily scratched.

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4 years ago
Find the weighted average of these values. Col1 Value 5.00 6.00 7.00Col2 Weight 75.0 % 15.0 % 10.0 %
Nadya [2.5K]

Answer:

5.35

Explanation:

Value   5.00        6.00       7.00

Weight 75.0%     15.0%      10.0 %

We can determine the weighted average of these values using the following expression.

Weighted average = ∑ wi × xi

where,

w: relative weight

x: value

Weighted average = 5.00 × 0.750 + 6.00 × 0.150 + 7.00 × 0.100

Weighted average = 5.35

7 0
3 years ago
A man weighs 185 lb. What is his mass in grams?<br> Please show work.<br> Thank you
Vera_Pavlovna [14]

Answer:

83914.52 grams

Explanation:

Given that,

Weight of a man is 185 lb

We need to find his weight in grams

For this, we must know the relation between lb and grams.

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1 lb = 453.592 grams

To find the mass of man in grams, the step is :

185 lb = (453.592 × 185) grams

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So, the mass of a man is 83914.52 grams.

8 0
4 years ago
Write a half-reaction for the oxidation of the manganese in MnCO3(s) to MnO2(s) in neutral groundwater where the carbonate-conta
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Answer:

The half-reaction for the oxidation of the manganese in MnCO_3(s) to MnO_2(s).:

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Explanation:

MnCO_3+H_2O\rightarrow MnO_2(s)+HCO_3^{-}

Let us say the medium in which reaction is taking place is an acidic medium. And balancing in an acidic mediums done as;

Step 1: Balance all the atom beside oxygen and hydrogen atom;

MnCO_3+H_2O\rightarrow MnO_2(s)+HCO_3^{-}

Manganese and carbon are balanced.

Step 2: Balance oxygen atom adding water on the required side:

MnCO_3+H_2O+H_2O\rightarrow MnO_2(s)+HCO_3^{-}

MnCO_3+2H_2O\rightarrow MnO_2(s)+HCO_3^{-}

Step 3: Now balance hydrogen atom by adding hydrogen ion on the required side:

MnCO_3+2H_2O\rightarrow MnO_2(s)+HCO_3^{-}+3H^+

6 0
3 years ago
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