Answer: from the Zn anode to the Cu cathode
Justification:
1) The reaction given is: Zn(s) + Cu₂⁺ (aq) -> Zn²⁺ (aq) +Cu(s)
2) From that, you can see the Zn(s) is losing electrons, since it is being oxidized (from 0 to 2⁺), while Cu²⁺, is gaining electrons, since it is being reduced (from 2⁺ to 0).
3) Then, you can already tell that electrons go from Zn to Cu.
4) The plate where oxidation occurs is called anode, and the plate where reduction occus is called cathode.
So you get that the electrons flow from the anode (Zn) to the cathode (Cu).
Always oxidation occurs at the anode, and reduction occurs at the cathode.
N=N₀*2^(-t/T)
N₀=200 g
T=10 d
t=30 d
N=200*2^(-30/10)=25 g
25 g will remain
A heat because heat is the transfer of energy.
Answer:B
Explanation:As the water heats up the particles will speed up hitting and colliding with each other which makes the water hot
The fraction of gas phase molecules is calculated by the division of final pressure to the initial pressure.
Fraction = 
(1)
Here, initial pressure = 1.0 atm
final pressure = 
First, convert torr into atm
1 atm = 760 torr
final pressure = 
= 
Now, put the value of initial and final pressure in formula (1)
Fraction = 
= 
Thus, fraction of the gas phase molecules = 
