Answer:
3.5 × 10⁵ g of salt
Explanation:
<em>What is the mass (grams) of salt in 10.0 m³ of ocean water?</em>
We have this data:
- 1.000 mol salt is equal to 58.44 g salt
- 1.0 L of ocean water contains 0.60 mol of salt
We will need the following relations:
We can use proportions:
Answer:
Do your project by yourself
<span>A 50 kg student runs up a flight of stairs that is 6 m high. How much work is done? 3000 J. Calculate the work done when a force of 1 N moves a book 2 m. 2 J .... 200 W, 100 W. Calculate the power expended when a 500. N barbell is lifted 2.2 m in 2.0 seconds. 550 W. energy. the property of an object or system that ...</span>
Out of the following given choice:
A. The increase in
the airspace occupied by vinegar molecules
B. The chemical reaction with nerves, which is slower than
other sensory processes
C. Attractive forces between the air and vinegar molecules
D. Random collisions between the air and vinegar molecules.
<span>The answer is
D. While the particles may be
moving at high velocities even at room
temperatures, the delay is due to the numerous collisions
between the vinegar molecules and the air molecules.This changes the vinegar’s
molecules directions from straight lines to random unpredictable paths</span>
