What is the problem u need help with
Given the percentage composition of HC as C → 81.82 % and H → 18.18 %
So the ratio of number if atoms of C and H in its molecule can will be:
C : H = 81.82 12 : 18.18 1 C : H = 6.82 : 18.18 = 6.82 6.82 : 18.18 6.82 = 1 : 2.66 ≈ 3 : 8
So the Empirical Formula of hydrocarbon is:
C 3 H 8
As the mass of one litre of hydrocarbon is same as that of C O 2 The molar mass of the HC will be same as that of C O 2 i.e 44 g mol
Now let Molecular formula of the HC be ( C 3 H 8 ) n
Using molar mass of C and H the molar mass of the HC from its molecular formula is:
( 3 × 12 + 8 × 1 ) n = 44 n So 44 n = 44 ⇒ n = 1
Hence the molecular formula of HC is C 3 H 8
Does that help?
Answer:
equation (4.16) depends on Boyle's law and Charles' law. The above relates the adjustment in perfect gas volume to the progressions in winning weight and temperature, separately. Moreover, equation (4.16) is alluded to as the condition of state for a perfect gas.
hope it helps:))
Because when you compress something, you compress an object to either tighten or get it smaller.
Since liquids have no shape of their own, you cannot squeeze or squish it to tighten/get it smaller.
Hopes this helps <span />
<span>According to Le Chatelier's Principle, the position of
equilibrium moves to counteract the change, the position of equilibrium
will move so that the concentration of
products of chemical reaction increase, if:</span>
<span>1) increase temperature, because this endothermic reaction.</span>
<span>2) increase concentration of reactant.</span>
<span>3) decrease pressure of the system, so reaction moves to direction where is more molecules.</span>
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