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3 years ago

Where does the energy of water at the top of the waterfall come from?

1 answer:

6 0

At the top of the waterfall, the water is higher in the gravitational field of the Earth and has gravitational potential energy. When it falls, the potential energy turns into kinetic energy.

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What is the current in mA through a 500 Ω resistor that is connected to a 1.5 V battery? Show all calculations using Ohm’s law (

Ludmilka [50]

Answer:

3 mA.

Explanation:

The following data were obtained from the question:

Resistor (R) = 500 Ω

Potential difference (V) = 1.5 V

Current (I) =.?

Using the ohm's law equation, we can obtain the current as follow:

V = IR

1.5 = I x 500

Divide both side by 500

I = 1.5 / 500

I = 3×10¯³ A.

Therefore, the current in the circuit is 3×10¯³ A.

Finally, we shall convert 3×10¯³ A to milliampere (mA).

This can be obtained as follow:

Recall:

1 A = 1000 mA

Therefore,

3×10¯³ A = 3×10¯³ × 1000 = 3 mA

Therefore, 3×10¯³ A is equivalent to 3 mA.

Thus, the current in mA flowing through the circuit is 3 mA.

3 0

3 years ago

a shopping bag can provide an upward force of 65N before breaking. A shopper puts 5 kg of groceries in the bag. If the shopper t

kipiarov [429]

Answer:

Since Force is Mass * Acceleration, the equation would be:

5kg * 2m^2 = 10N

(10N is less than 65N)

Therefore, it would not be enough force for the bag to break.

6 0

4 years ago

Calculate the average net force.

MrRa [10]

Answer:

<h2>given</h2>

mass = 3950 kg

speed= 25m/ sec

time= 10.5 sec

force

<h2>Solution</h2>

<h3>☄️Formula of force </h3>

$\fbox{f = m.a}$

To find the force we need to find the Acceleration first.

accleration= change in Velocity/time

accleration= 25/10.5

accleration= 2.38 m/sec²

put the value of accleration in the formula of force

force = Mass . accleration

force = 3950 x 2.38

<h3>☄️force = 9,401 Newton</h3>

3 0

3 years ago

The products of one turn of dark reaction cycle are called

harina [27]

Light Independent Reactions

5 0

3 years ago

A wave of amplitude 20mm has intensity Ix. Another wave of the same frequency but of amplitude 5mm has an intensity Iy.

Alexeev081 [22]

Answer:

(C) 16

Explanation:

Given:

The amplitude of first wave (s₁) = 20 mm

The amplitude of second wave (s₂) = 5 mm

Intensity of first wave = Iₓ

Intensity of second wave = $I_y$

The intensity associated with a wave depends on the amplitude of the wave.

The intensity (I) is directly proportional to the square of the amplitude (s) of the wave and is expressed as:

$I=ks^2\\Where\ k\to constant\ of\ proportionality$

Now, the intensities of the two waves are given as:

$I_x=ks_1^2=k(20)^2\\\\I_y=ks_2^2=k(5)^2$

Dividing both the intensities, we get:

$\frac{I_x}{I_y}=\frac{k(20)^2}{k(5)^2}\\\\\frac{I_x}{I_y}=\frac{400}{25}\\\\\frac{I_x}{I_y}=16$

Therefore, the option (C) is correct.

5 0

3 years ago