The question requires that we have to state the hypothesis:
null hypothesis;H0: u1 < u2, the alternate hypothesis;H1: u1 > u2. The one tail test is what is to be used.
<h3>A.
How to state the hypothesis</h3>
H0: u1 < u2
H1: u1 > u2
The one tail test statistic is what is to be used here
<h3>B.
standard error </h3>

= 1.49
The df = 17 + 15 - 2
= 30
test statistic = 18.9 - 17.4 / 1.49
= 1.007
We have the critical value on excel as T.INV(0.9,30)
= 1.310
E. At 0.1, we can conclude that t-value (1.007) does not lies in the rejection area. We fail to reject the null hypothesis. Hence we conclude that the mean vacation with the unlimited plan is greater.
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Im late but i had this test its car A < rate of car B hope it helps
477900 there you go use a calculator next time ;)
*) 2/4+3i
2+3i
I'm not sure is that right or wrong
Given:
The figure of a rhombus QRST.
To find:
A. The value of x.
B. The measure of angle RQP.
Solution:
A. We need to find the value of x.
We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.
[Right angle]
Divide both sides by 5.
Therefore, the value of x is 15.
B. We need to find the measure of angle RQP.
From the given figure, it is clear that

Putting
, we get



Therefore, the measure of angle RQP is 33 degrees.