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Alik [6]
3 years ago
13

After being rearranged and simplified, which of the following equations could be solved using the quadratic formula? Check all t

hat apply.​

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
7 0
It’s Johnny works on bobs burgers barn and makes $8.10 an hour he works 91/2 hours each week he is saving his money to buy a Nintendo switch witch costs $299.99 how many weeks must Johnny work before he can purchase the game about how many hours must he work?
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Sammy scored “six points more than 10 times the number of cards in his hand”
Nady [450]

Answer:

it's the second one because if c repeats the number it will repeat 10 six times it like

Step-by-step explanation:

10 x 6 which equals 60

5 0
3 years ago
Anna's has 30 feet of fence to go around her garden. The lettuce will be in a 8 feet × 5 ft section and the carrots will be in a
Dmitry [639]
8 * 5= 40
And 2*7 =14
Add them equal 54
No
8 0
3 years ago
Pleaseeeee helpppppp
Bumek [7]

Answer:

Step-by-step explanation:

\frac{b}{-3}+4< 13

Step 1: Subtract 4 form both sides

Step 2: Multiply both sides by (-3). when we are multiplying by (-3) the < will change to >.

\frac{b}{-3}+4-4 9*-3\\\\b > -27

8 0
3 years ago
Read 2 more answers
A lake in East Texas was stocked with 3,000 trout in the year 2000. The number of fish in the lake is modeled by f(x) = 3000 + 1
Maru [420]

Answer: x ≥0,y ≥3000

Step-by-step explanation:

that’s what i put and got it right so ‍♀️

5 0
3 years ago
Which of the equations are true identities? A. N ( n − 2 ) ( n + 2 ) = n 3 − 4 n B. ( x + 1 ) 2 − 2 x + y 2 = x 2 + y 2 + 1
ICE Princess25 [194]

Answer:

Both A and B are true identities

Step-by-step explanation:

A. N ( n − 2 ) ( n + 2 ) = n 3 − 4 n

We need to show that (left-hand-side)L.H.S = R.H.S (right-hand-side)

So,

 n ( n − 2 ) ( n + 2 ) = n(n² - 2²)     (difference of two squares)

                               = n³ - 2²n       (expanding the brackets)

                               = n³ - 4n         (simplifying)

So,                L.H.S  = R.H.S

B. ( x + 1 )² − 2x + y² = x² + y² + 1

We need to show that (left-hand-side)L.H.S = R.H.S (right-hand-side)

So,

( x + 1 )² − 2x + y² = x² + 2x + 1 - 2x + y²   (expanding the brackets)

                             = x² + 2x - 2x + 1  + y²   (collecting like terms)

                             = x² + 1 + y²        

                             = x² + y² + 1                    (re-arranging)

So,              L.H.S  = R.H.S

So, both A and B are true identities since we have been able to show that L.H.S  = R.H.S in both situations.

7 0
3 years ago
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