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4 years ago

Describe what the absolute value function does

Mathematics

2 answers:

Gwar [14]4 years ago

4 0

It’s how far the number is from 0.

Vilka [71]4 years ago

3 0

It is the distance the number is from 0

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Write the expressions "Four times the difference of a number and 7 is 32", "One third of a number is 12 less than the number its

Anna71 [15]

Part 1) "Four times the difference of a number and $7$ is $32$ "

Let

x--------> the number

we know that

the expressions is equal to

$4(x-7)=32$

therefore

the answer part 1) is

$4(x-7)=32$

Part 2) "One third of a number is $12$ less than the number itself"

Let

x--------> the number

we know that

the expressions is equal to

$\frac{1}{3} x=(x-12 )$

therefore

the answer part 2) is

$\frac{1}{3} x=(x-12 )$

Part 3) "Ten increased by the quotient of a number and $2$ is $-15$ "

Let

x---------> the number

we know that

the expressions is equal to

$10+ (\frac{x}{2} )= -15$

therefore

the answer Part 3) is

$10+ (\frac{x}{2} )= -15$

Part 4) "One less than the product of a number and $3$ is $5$ more than the number itself"

Let

x---------> the number

we know that

the expressions is equal to

$(3x)-1=5+x$

therefore

the answer Part 4) is

$(3x)-1=5+x$

3 0

3 years ago

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Shtirlitz [24]

Answer:

Step-by-step explanation:

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3 years ago

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A 12 by 15 inch picture is mounted on a wall and surrounded by a border of uniform width.

Ludmilka [50]

Answer:

finish your exam please i am a supervisor

Step-by-step explanation:

5 0

3 years ago

Jack bought 3 protein bars for a total of $4.26 which equation could be used to find the cost c on dollars of each protein bar

kramer

Answer: (C)

Solution:
Jack bought 3 bars for $4.26 thus the cost of each bar can be defined as:

$c = \frac{4.26}{3}$ ⇒ $3c = 4.26$

3 0

3 years ago

Exercise 5.2. Suppose that X has moment generating function

soldi70 [24.7K]

Answer:

a) Mean, E(X) = - 0.5

Variance = = 9.25

b) $M_{X}(t)=E(e^{tX})$

⇒ $=\sum e^{tx}p(x)$

⇒ $=\frac{1}{2}+\frac{1}{3}e^{-4t}+\frac{1}{6}e^{5t}$

Step-by-step explanation:

Given:

moment generating function of X as:

MX(t) = $\frac{1}{2} + \frac{1}{3}e^{-4t} + \frac{1}{6} e^{5t}$

a) Now

Mean, E(X) = $M_{X}'(t=0)$

Thus,

$M_{X}'(t)=\frac{1}{3}(-4)e^{-4t}+\frac{1}{6}(5)e^{5t}$

$M_{X}'(t)=\frac{-4}{3}e^{-4t}+\frac{5}{6}e^{5t}$

also,

$E(X^{2})=M_{X}''(t=0)$

Thus,

$M_{X}''(t)=\frac{-4}{3}(-4)e^{-4t}+\frac{5}{6}(5)e^{5t}$

$M_{X}''(t)=\frac{16}{3}e^{-4t}+\frac{25}{6}e^{5t}$

Therefore,

Mean, E(X) = $M_{X}'(t=0)=\frac{-4}{3}e^{-4(0)}+\frac{5}{6}e^{5(0)}$

Mean, E(X) = - 0.5

and

$E(X^{2})=M_{X}''(t=0)=\frac{16}{3}e^{-4(0)}+\frac{25}{6}e^{5(0)}$

$E(X^{2})$ = 9.5

also,

Variance(X) = E(X²) - E(X)²

⇒ 9.5 - (-0.5)²

= 9.25

b) Now,

Let f(x) be the PMF of X

Thus,

$M_{X}(t)=E(e^{tX})$

⇒ $=\sum e^{tx}p(x)$

⇒ $=\frac{1}{2}+\frac{1}{3}e^{-4t}+\frac{1}{6}e^{5t}$

Therefore,

at x = 0, P(x) = $\frac{1}{2}$

at x= - 4 ,P(x) = $\frac{1}{3}$

at x = 5, P(x) = $\frac{1}{6}$

Thus,

E(X) = $\sum xP(x)=0(\frac{1}{2})+(-4)(\frac{1}{3})+5(\frac{1}{6})$

E(X) = - 0.5

also, $E(X^{2})=\sum x^{2}P(x)=0^{2}(\frac{1}{2})+(-4)^{2}(\frac{1}{3})+5^{2}(\frac{1}{6})$

$E(X^{2})$ = 9.5

Hence,

Var(X) = E(X²) - E(X)²

⇒ 9.5 - (-0.5)²

= 9.25

4 0

4 years ago