Answer:
a) 
b) 
c) 
d) 
And we can find this probability with this formula from the Bayes theorem:
Step-by-step explanation:
For this case we assume that the random variable X follows this distribution:

Part a
The probability density function is given by the following expression:


Part b
We want this probability:

And we can use the cumulative distribution function given by:

And replacing we got:

Part c
We want this probability:

And we can use the CDF again and we have:

Part d
We want this conditional probabilty:

And we can find this probability with this formula from the Bayes theorem:

This lot has the shape of a trapezoid. Regard the 2 different lengths as 160' and 80' and the width 100'
Applying the formula for the area of a trapezoid:
80' + 160'
A = ----------------- * 100' = 24000 ft^3
2
0.39 inches.
Or 0.4 if you want to round it ;3
It is A sure do hope this helps