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2 years ago

Let's Apply Solve for the surface area of the following figures. please i need this rn

Mathematics

1 answer:

Dafna1 [17]2 years ago

3 0

Answer:

Step-by-step explanation:

1) Surface area of a square = s*s = 12*12 = 144 in

2) Surface area of a Cone = A=πr(r+h2+r2) = 3.142*4(4+22*2+4*2) = 351.904 cm^2

3) S.A of a Cylinder =2πrh+2πr2 = 2*3.142*2*14 + 2*3.142*2*2 = 201.088 m^2

4) S.A of a square Pyramid = a^2 + 2a squareroot (a^2/4 + h^2) = 516.5m^2

5) S.A of a Sphere = 4*pie*r^2 = 4* 3.142*15^2 = 2827.8mm^2

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3 years ago

The part of a cylindrical soup can that is covered by the label is 8.5 cm tall and has a diameter of 6.5 cm. What is the area of

julia-pushkina [17]

Answer:

$180.4~cm^2$

Step-by-step explanation:

<u>Surface Area</u>

The surface area of a cylinder of height h and radius r is given by:

$A=2\pi rh$

It only covers the lateral side of the cylinder. If both the top and the bottom sides are to be included, then:

$A=2\pi rh+2\pi r^2$

The label will cover only the lateral side of the soup can that has a height of h=8.5 cm and a diameter of 6.5 cm. We need to calculate the radius which is half of the diameter r=6.5 cm / 2 = 3.25 cm.

Now we calculate the side area of the can:

$A=2\pi (3.25)(8.5)$

$A=173.6~cm^2$

We need to add the 0.8 cm overlap to the total area already calculated. This overlap has 0.8 cm of width and 8.5 cm of height, so this overlap area is:

$A_o= 0.8*8.5=6.8~cm^2$

The total area of the label is:

$A=173.6~cm^2+6.8~cm^2=180.4~cm^2$

The area of the label is $\mathbf{180.4~cm^2}$

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3 years ago

Let's Apply Solve for the surface area of the following figures. ​please i need this rn​

Let's Apply Solve for the surface area of the following figures. please i need this rn