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Rina8888 [55]
2 years ago
12

Let's Apply Solve for the surface area of the following figures. ​please i need this rn​

Mathematics
1 answer:
Dafna1 [17]2 years ago
3 0

Answer:

Step-by-step explanation:

1) Surface area of a square = s*s = 12*12 = 144 in

2) Surface area of a Cone =  A=πr(r+h2+r2) = 3.142*4(4+22*2+4*2) = 351.904 cm^2

3) S.A of a Cylinder =2πrh+2πr2 = 2*3.142*2*14 + 2*3.142*2*2 = 201.088 m^2

4) S.A of a square Pyramid = a^2 + 2a squareroot (a^2/4 + h^2) = 516.5m^2

5) S.A of a Sphere = 4*pie*r^2 = 4* 3.142*15^2 = 2827.8mm^2

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Answer:

2Pi/8

Step-by-step explanation:

6 0
3 years ago
What is 694 divided by 41 and what is the remainder please help thank you
Studentka2010 [4]
16... Remainder of 38

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4 0
3 years ago
Read 2 more answers
Solve for x and graph the solution on the number line<br> 15 &gt; 2x – 9 &gt; -23
Monica [59]

The answer is 12>x>-7

Step-by-step explanation:

it's first divided into 2 parts

1 . 15 > 2x - 9

2. 2x - 9 > -23

Then solve them individually.

let's do it,

<u>First half</u>

15 > 2x - 9

15+9 > 2x

24 > 2x

24/2 > x

12>x

<u>Second half</u>

2x-9>-23

2x>-23+9

2x>-14

x>-14/2

x>-7

<u>Joining of the two halves</u>

We have :

12>x>-7

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B2%7D%20%2B1%20%3D%20%5Csqrt%7B3%7D%20" id="TexFormula1" title=" \frac{x}{2
Tresset [83]
I hope this helps you

3 0
3 years ago
A map of a new dog park shows that it is triangular and that the sides measure 18.5m, 36.9m, and 16.9m. Are the dimensions corre
r-ruslan [8.4K]
In order to check whether the length of the sides are applicable to form a triangle is that we have to make sure that the sum of the length of two side should be greater than the third side.

<span>18.5 m, 36.9 m, and 16.9 m
18.5 m < </span><span>36.9 m +16.9 m
</span>36.9 m < 18.5<span> m +16.9 m
</span>16.9 m < 18.5 m + <span>36.9 </span>m

So the dimensions are correct!
5 0
3 years ago
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