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Lunna [17]
3 years ago
8

AEFG - ALMN. Find LM.

Mathematics
1 answer:
ollegr [7]3 years ago
4 0

Answer:

The solution is 2.5. The problem can be solved using the proportion:  

2

4

=

x

5

Step-by-step explanation:

I hope it makes since =)

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inessss [21]

Answer:

The  same (42 degrees)

Step-by-step explanation:

This is because the angles are congruent or the same.

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IMAGE ATTACHED please help giving 50 points
alexdok [17]

Answer:

(4,1)

Step-by-step explanation:

when points are reflected on the y-axis you switch your x coordinate from positive to negative or the other way around the y coordinate stays the same.

(2,1) reflected is (-2,1)

(7,4) reflected is (-7,4)

(-8,-4) reflected is (8,-4)

so (-4,1) reflected is (4,1)

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2 years ago
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For 100​ births, P(exactly ​girls) and ​P( or more ​girls). Is girls in 100 births a significantly high number of​ girls? Which
madreJ [45]

Answer;

The relevant probability is 0.136 so the value of 56 girls in 100 births is not a significantly high number of girls because the relevant probability is greater than 0.05

Step-by-step explanation:

The complete question is as follows;

For 100 births, P(exactly 56 girls = 0.0390 and P 56 or more girls = 0.136. Is 56 girls in 100 births a significantly high number of girls? Which probability is relevant to answering that question? Consider a number of girls to be significantly high if the appropriate probability is 0.05 or less V so 56 girls in 100 birthsa significantly high number of girls because the relevant probability is The relevant probability is 0.05

Solution is as follows;

Here. we want to know which of the probabilities is relevant to answering the question and also if 56 out of a total of 100 is sufficient enough to provide answer to the question.

Now, to answer this question, it would be best to reach a conclusion or let’s say draw a conclusion from the given information.

The relevant probability is 0.136 so the value of 56 girls in 100 births is not a significantly high number of girls because the relevant probability is greater than 0.05

7 0
2 years ago
For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim
ICE Princess25 [194]

Answer:

Part a) The area of the figure is \frac{9}{2}(4+\pi )\ cm^{2}

Part b) The perimeter of the figure is 3(2+2\sqrt{2}+ \pi)\ cm

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

AB=6\ cm, BC=6\ cm

The area of the half square ABC is equal to find the area of triangle ABC

so

A1=\frac{1}{2}*6*6=18\ cm^{2}

<u>Find the area of the semicircle</u>

The area of the semicircle is equal to

A2=\pi r^{2}/2

we have that

r=6/2=3\ cm

substitute

A2=\pi (3)^{2}/2

A2=(9/2) \pi\ cm^{2}

The area of the figure is equal to

18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

P=AB+AC+length\ CB

we have

AB=6\ cm

Applying Pythagoras theorem

AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm

Remember that

the circumference of a semicircle is equal to

C=\frac{1}{2}2\pi r=\pi r

r=6/2=3\ cm

C=\pi(3)

C=3 \pi\ cm

The perimeter of the figure is equal to

P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm

Simplify

P=3(2+2\sqrt{2}+ \pi)\ cm

5 0
3 years ago
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TEA [102]

The answer is TRUE. The parallelogram must be a rectangle

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