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2 years ago

8

We know that logarithmic functions are a bit more unusual than functions we’ve seen in the past, such as linear, exponential, qu

adratic, and even polynomial and radical functions. We rarely see them in examples, so what’s their real purpose as functions?

1 answer:

AnnyKZ [126]2 years ago

7 0

Answer:

Step-by-step explanation:

can you re-phrase that please then i can answer

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You have a set of 10 cards—five red and five blue. Each group of five colored cards is numbered one through five.What is the pro

MatroZZZ [7]

The probability of drawing the Red 4 is 1 in 10. So, the chances of getting it would be 1/10.The probability is also the same for drawing the Blue 4, so it would be 1/10 also.

The probability assignment for this problem is the classical method which means that experimental outcomes are equally likely. So, just multiply the probability of the first event to the second event.
= 1/10 * 1/10 = 1/100
The probability of getting the blue and red four is 1/100 or 0.01.

7 0

3 years ago

Read 2 more answers

What is the sum of the exterior angles, one at each vertex, of a polygon with 20 sides?A.20B.360C.180D. We need more information

ale4655 [162]

The measure of an exterior angle in a polygon with n sides is given by:

$a_n=\frac{360}{n}$

So, for n = 20, we have the measure of the exterior angles of the polygon with 20 sides:

$\begin{gathered} a_{20}=\frac{360}{20} \\ a_{20}=18\degree \end{gathered}$

Now, to find the sum of all exterior angles, let's multiply the exterior angles by the number of sides of the polygon:

$\begin{gathered} S_{20}=a_{20}\cdot n \\ S_{20}=18\cdot20 \\ S_{20}=360\degree \end{gathered}$

Therefore the sum is equal to 360°, correct option: B.

(The sum of exterior angles of a polygon with n sides is always equal to 360°)

7 0

1 year ago

Y+2=-3(x-2) solve for y

luda_lava [24]

Your answer will be y=-3x+4

8 0

3 years ago

Read 2 more answers

Two students use different methods to solve this multiplication problem: 1/2 • -4 4/5

sesenic [268]

Solution:

$\frac{1}{2}\times-4 \frac{4}{5}$

As one of the fraction is a proper fraction and another one is Mixed fraction.

There are two methods of solving it.

1. $\frac{1}{2}\times-4 \frac{4}{5}=\frac{1}{2} \times \frac{-24}{5}=\frac{-12}{5}=-2\frac{2}{5}$

2. $\frac{1}{2}\times-4 \frac{4}{5}=\frac{1}{2}[-4-\frac{4}{5}]=\frac{1}{2}\times (-4)+\frac{1}{2}\times\frac{-4}{5}=-2+\frac{-2}{5}=\frac{-10-2}{5}=\frac{-12}{5}=-2\frac{2}{5}$ →→Here i have used Distributive property with respect to addition and Subtraction i.e a×(b+c)= a ×b + a×c or a×(b-c)=a×b-a×c

Now, you can fill the blanks by yourself.

5 0

3 years ago

Compare the sets of numbers given and place them in the correct column or incorrect column. K: Move to Bottom 0.125 < 1 8 0.4

polet [3.4K]

Answer:

Correct Comparison:

1st

3rd

5th

6th

Incorrect Comparison:

the rest of them

Step-by-step explanation:

left-right, top-bottom order btw

6 0

3 years ago