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Burka [1]
4 years ago
6

Are 2.8 and 2.800 equal? PLEASE HELP THIS IS DUE TOMMORROW!

Mathematics
2 answers:
lutik1710 [3]4 years ago
8 0
They are the zeros have no meaning
ASHA 777 [7]4 years ago
5 0
Yes they are because the zeros dont have any value
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Use elimination and explain
Temka [501]

Answer:

The elimination method for solving systems of linear equations uses the addition property of equality. You can add the same value to each side of an equation. So if you have a system: x – 6 = −6 and x + y = 8, you can add x + y to the left side of the first equation and add 8 to the right side of the equation

4 0
3 years ago
Fruit Company A recently released a new applesauce. By the end of its first year, profits on this product amounted to $37,100. T
Anastasy [175]

Answer: 11 year

P(1) = 37,100

P(4) = 58,400

The linear equation (for x ≥ 1)

P(x) = 37,100 + a(x-1)

For x = 4

58,400 = 37,100 + a(4-1)

58,400 - 37,100 = 3a

21300 = 3a

a = 7100

So, the linear equation:

P(x) = 37100 + 7100*(x-1)

P(x) = 37100 + 7100x - 7,100

P(x) = 7100x + 30000

To find when the profit should reach 108100, we can substitute P(x) by 108100.

108100 = 7100x + 30000

108100 - 30000 = 7100x

78100 = 7100x

x = 78100/7100

x = 11

Answer: 11 year

7 0
2 years ago
0.24 times 0.4<br> Equals
Komok [63]

That would be 0.24(0.4). First, estimate the result: 0.24 is about 1/4, and (1/4)(0.4) is about 0.1.

0.24(0.4) = 0.096 (which agrees with the estimated answer, 0.1).

6 0
4 years ago
Read 2 more answers
Write 2.8 as a mixed number in a simplest form
Elena-2011 [213]
It would be 2 4/5............i hope this helps you
3 0
3 years ago
Read 2 more answers
Sasha performs an experiment. She chooses one marble from each of three sacks. The first sack has black (B) and white (W) marble
Paladinen [302]

Answer:

Option D is correct

Step-by-step explanation:

From the question, we have:

Sack\ 1: B, W

Sack\ 2: G, Y

Sack\ 3: S, R

Required

The tree diagram

The selection process is as follows:

Sack\ 1: B, W

Sack\ 1\ and\ Sack\ 2: B (G,Y); W(G,Y) -- i.e. we write sack 2 as a subset of 1

Sack\ 1, 2\ and\ 3: B (G(S,R),Y(S,R)); W(G(S,R),Y(S,R)) -- i.e. we write sack 3 as a subset of 2

<em>The only tree diagram that illustrates this is: option D</em>

5 0
3 years ago
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