Find the domain of the graph

Which linear inequality is represented by the graph? (A)y ≤1/3 x − 1 (B)y ≥ x − 1 (C)y < 3x − 1 (D)y > 3x − 1

lubasha [3.4K]

The equation of the line is $\boxed{y \geqslant \frac{1}{3}x - 1}.$

Further explanation:

The linear equation with slope $m$ and intercept $c$ is given as follows.

$\boxed{y = mx + c}$

The formula for slope of line with points $\left( {{x_1},{y_1}} \right)$ and $\left( {{x_2},{y_2}} \right)$ can be expressed as,

$\boxed{m = \frac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}}$

Given:

Explanation:

The line intersects y-axis at $\left( {0, - 1} \right)$ . Therefore, the y-intercept is $-1.$

The line passes through the points $\left( {0, - 1} \right)$ and $\left( {3,0} \right).$

The slope can be obtained as follows,

$\begin{aligned}m&= \frac{{0- \left( {- 1} \right)}}{{3 - 0}}\\&= \frac{1}{3}\\\end{aligned}$

Substitute $\dfrac{1}{3}$ for m, $3$ for $x$ and $0$ for $y$ in equation $y = mx + c$ to obtain the value of $c$ .

$\begin{aligned}0& \frac{1}{3} \cdot 3 + c\\- 1&=c\\\end{aligned}$

To check whether the equation includes origin substitute 0 for x and 0 for y in equation $y \geqslant \dfrac{1}{3}x - 1.$

$\begin{aligned}0&\geqslant \frac{1}{3} \times 0 - 1 \\0&\geqslant - 1\\\end{gathered}$

The statement is true. The equation contains origin.

The equation of the line is $\boxed{y \geqslant \frac{1}{3}x - 1}.$

Learn more:

Learn more about inverse of the functionhttps://brainly.com/question/1632445.
Learn more about equation of circle brainly.com/question/1506955.
Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Linear equation

Keywords: numbers,slope, slope intercept, inequality, equation, linear inequality, shaded region, y-intercept, graph, representation, origin.

7 0

3 years ago

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I research or chooses a random sample of registered voters in Kingsville he found that three out of every five voters surveyed s

ikadub [295]

8843737383737744444444

3 0

3 years ago

Based on the tax brackets, what’s the estimated total tax due for a single taxpayer with a taxable income of $43,500?

inysia [295]

Answer:

C. $5,509.50

Step-by-step explanation:

The computation of the estimated total tax due in case of taxable income for $43,500 is shown below:

Since in the question the income brackets and based on the income the different tax is to be charged

For $9,525, the 10% tax is charged i.e

$= \$9,525 \times 10\%$

= $952.50

Upto $38,700, the 12% tax is charged i.e

$= (\$38,700 - \$9,526) \times 12\%$

= $3,500.88

The remaining amount left is

$= (\$43,500 - \$38,701) \times 22\%$

= $1,055.78

Now the total tax due is

= $952.50 + $3,500.88 + $1,055.78

= $5,509.16 approx i.e $5,509.50

6 0

3 years ago

A sample of 100 people is classified by gender (male/female) and by whether they are registered voters. The sample consists of 8

uysha [10]

Answer:

12

Step-by-step explanation:

Given :

Male Female Total

Registered 60

Non registered 40

Total 20 80

Solution :

N= 100

Formula of expected frequency = $E_{ij}=\frac{T_i \times T_j}{N}$

$E_{ij}$ = expected frequency for the ith row/jth columm.

$T_i$ = total in the ith row

$T_j$ = total in the jth column

N = table grand total.

So, using formula $E_{11}=\frac{T_1 \times T_1}{100}$

$E_{11}=\frac{60 \times 20}{100}$

$E_{11}=12$

$E_{12}=\frac{T_1 \times T_2}{100}$

$E_{12}=\frac{60 \times 80}{100}$

$E_{12}=48$

$E_{21}=\frac{T_2 \times T_1}{100}$

$E_{21}=\frac{40 \times 20}{100}$

$E_{21}=8$

$E_{22}=\frac{T_2 \times T_2}{100}$

$E_{22]=\frac{80 \times 40}{100}$

$E_{22}=32$

Expected frequency table

Male Female Total

Registered 12 48 60

Non registered 8 32 40

Total 20 80

So, the expected frequency for males who are registered voters are $E_{11}=12$

5 0

3 years ago

Compare the decimals 7,231.60 and 7,231.6. Which comparison is correct? A. 7,231.60 < 7,231.6 B. 7,231.60 = 7,231.6 C. 7,231.

Ilia_Sergeevich [38]

B. 7,231.60 = 7,231.6

3 0

3 years ago

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