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HACTEHA [7]
4 years ago
5

Solve -27p²q²+6p³-2p⁴-q³​

Mathematics
1 answer:
rewona [7]4 years ago
4 0

Answer:

-27p^2 q^2 +6p^3 -2p^4 -q^3

Step-by-step explanation:

COMBINE LIKE TERMS

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A triangular field has sides of 218.5 m and 224.5 m, and the angle between them measures 58.20 . Find the area of the field.
telo118 [61]

Answer:

<em>20,845 square meters</em>

<em />

Step-by-step explanation:

We can use the formula for area of a triangle to figure this out easily.

Area = \frac{1}{2}abSinC

Where

a and b are the two side lengths of the triangle given, and

C is the ANGLE BETWEEN the two sides

<em>Clearly, we see that one side is 218.5 and other is 224.5 and the angle between them is given by 58.2 degrees. Now we simply substitute these values into the formula and get the area:</em>

<em>A=\frac{1}{2}abSinC\\A=\frac{1}{2}(218.5)(224.5)Sin(58.2)\\A=20,844.99</em>

<em />

<em>Rounding, we get the area to be 20,845 square meters</em>

5 0
4 years ago
A company has budgeted $21,200 to buy TV ads. A TV ad costs $6,575 per
amm1812

Answer:

about 300

21200 rounded is 21000 and 6575 rounded is 7000

Step-by-step explanation:

21000÷7000=300

3 0
4 years ago
What is the equation of the graph below
aksik [14]

Answer:

The answer is B) y = Sin(3x)

Step-by-step explanation:

In order to find this, you need to look for how long it takes the period to repeat. This means other than the origin, we need to find the next place that the graph hits y = 0. In this case, it is at 2\pi/3. Since Sin2\pi = 0, we need what is inside of the parenthesis to equal 2\pi.

The only thing that you could multiply 2\pi/3 by to get 2\pim is 3. Therefore, we must have 3x in the original equation.

3 0
4 years ago
Two packages weigh 3.92 pounds and 2.8 pounds. How many times heavier Is the first package than the second?
avanturin [10]

3.92/2.8=1.4

Unless it’s reverse.

2.8/3.92=0.714285714285 and so on.

3 0
4 years ago
Drag each expression to the correct location on the model. Not all will be used
grandymaker [24]

Answer:     \dfrac{x^{2}+2x+1 }{\mathbf {x-1}} \cdot \dfrac{\mathbf {5x^{2} +15x-20} }{7x^{2} +7x}

Step-by-step explanation:

\dfrac{\dfrac{5x^{2} +25x+20}{7x} }{\dfrac{x^{2} +2x+1}{7x^{2} +7x} } =\dfrac{5x^{2} +25x+20}{7x} \times \dfrac{7x^{2} +7x}{x^{2} +2x+1}=\dfrac{5x^{2} +25x+20}{7x} \times \dfrac{7x(x +1)}{(x+1)^{2} }=\\\\=\dfrac{5x^{2} +25x+20}{x+1} =\dfrac{{5(x+1)(x+4)}}{x+1}=5(x+4)

5(x+4)=\dfrac{5(x-1) \cdot (x+4)}{x-1}=\dfrac{5x^{2} +15x-20}{x-1}

<em>Thus, the expressions will be used: (5x² + 15x - 20) and (x + 4).</em>

<em>Let's check:</em>

\dfrac{x^{2}+2x+1 }{\mathbf {x-1}} \cdot \dfrac{\mathbf {5x^{2} +15x-20} }{7x^{2} +7x} =\dfrac{(x+1)^{2} }{x-1}  \cdot \dfrac{5(x-1) \cdot (x+4)}{7x(x+1)} =\\\\=\dfrac{(x+1) \cdot 5 \cdot (x+4)}{7x} =\dfrac{5x^{2} +25x+20}{7x}

5 0
3 years ago
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