F(0)= -3 that’s your answer
Answer with explanation:
Let p be the proportion of adults have heard of the new electronic reader.
Given claim : The accompanying technology display results from a test of the claim that 38% of adults have heard of the new electronic reader.
i.e.
Then , the set of hypothesis will be :-

Since, the alternative hypothesis is two tailed , so the test is two-tailed test.
Also, it is given that the sample size : 
Number of adults showed that they have heard of a new electronic reader=522
So the sample proportion for adults have heard of the new electronic reader : 
The test statistic for proportion is given by :-
By using standard normal distribution table , the P-value for two tailed test corresponds to the obtained z-value =
Answer:
The p-value of the test statistic from the standard normal table is 0.0017 which is less than the level of significance therefore, the null hypothesis would be rejected and it can be concluded that there is sufficient evidence to support the claim that less than 20% of the pumps are inaccurate.
Step-by-step explanation:
Here, 1304 gas pumps were not pumping accurately and 5689 pumps were accurate.
x = 1304, n = 1304 + 5689 = 6993
The level of significance = 0.01
The sample proportion of pump which is not pumping accurately can be calculated as,
The claim is that the industry representative less than 20% of the pumps are inaccurate.
The hypothesis can be constructed as:
H0: p = 0.20
H1: p < 0.20
The one-sample proportion Z test will be used.
The test statistic value can be obtained as:

Answer:
25% of 1,000$.
Step-by-step explanation:
Answer:
We conclude that inequality describes all possible lengths of AB
Option C is true.
Step-by-step explanation:
We know that the sum of the lengths of any two sides of a triangle is greater than the length of the third side.
Now, checking the interval of the length of the side 'x', such as:
24 + 11 = 35
24 - 11 = 13
so the possible lengths of the side 'x' will be:
13 < x < 35
Therefore, we conclude that inequality describes all possible lengths of AB
Hence, option C is true.