3 years ago

Find the area of the rhombus

1 answer:

3 0

$TQ = \sqrt{ {PQ}^{2} - {PT}^{2} } = \sqrt{{20}^{2} - {16}^{2} } = \sqrt{144} = 12\: mm \\ Area:16 \times 12 \times 2 = 384\: {mm}^{2}$

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Answer:

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Step-by-step explanation:

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