Look at the fraction and decide which comment matches the situation

starting at home, nadia traveled uphill to the grocery store for 30 minutes at just 4 mph. she then traveled back home along the

ankoles [38]

Distance from home to store = 4 * 0.5 = 2 miles.
Time taken to return home = (2/12) * 60 =10 minutes.
Total distance traveled = 2 * 2 = 4 miles.
Total time taken = 30 + 10 = 40 minutes.
Average speed for entire trip = total distance / total time in hours.
$Average\ speed=\frac{4}{\frac{40}{60}}=\frac{4\times60}{60}=6\ mph$

3 0

3 years ago

Read 2 more answers

Help me .......................................

SpyIntel [72]

Answer:

X^3 AS THE NUMERATOR 8 AS THE DENOMINATOR

Step-by-step explanation:

6 0

3 years ago

25, 8, 10, 35, 5, 45, 40, 30, 20

Lera25 [3.4K]

B.) 37.5.. First you place all the numbers in order from least to greatest. Your mean is 25...and ur upper quartile because the 4 #'s fall even u add 35 and 40 and divide by 2... Which gives u upper quartile of 37.5 and lower quartile of 9. Hope this helps :)

4 0

3 years ago

Janeel has a 10-inch by 12-inch photograph. She wants to scan the photograph, then reduce the result

Vaselesa [24]

Complete Question:

Janeel has a 10 inch by 12 inch photograph. She wants to scan the photograph, then reduce the results by the same amount in each dimension to post on her Web site. Janeel wants the area of the image to be one eight of the original photograph. Write an equation to represent the area of the reduced image. Find the dimensions of the reduced image.

Correct Answer:

A) $(10-x)(12-x)=15$

B) Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

Step-by-step explanation:

a. Write an equation to represent the area of the reduced image.

Let the reduced dimensions is by x , So the new dimensions are

$length=10-x\\breadth=12-x$

According to question , Area of new image is :

⇒ $Area = \frac{1}{8}Length(breadth)$

⇒ $Area = \frac{1}{8}(10)(12)$

⇒ $Area = 15$

So the equation will be :

⇒ $(10-x)(12-x)=15$

b. Find the dimensions of the reduced image

Let's solve : $(10-x)(12-x)=15$

⇒ $120-10x-12x+x^2=15$

⇒ $120-22x+x^2=15$

⇒ $x^2-22x+105=0$

By Quadratic formula :

⇒ $x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

⇒ $x = \frac{22 \pm8 }{2}$

⇒ $x = \frac{22 +8 }{2} , x = \frac{22 -8 }{2}$

⇒ $x = 15 , x =7$

x = 15 is rejected ! as 15 > 10 ! Side can't be negative

⇒ $x =7$

Therefore, Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

5 0

2 years ago

mauricio estimates that the first module of the project could be completed in as few as 15 days or could take as many as 25 days

4vir4ik [10]

Answer:

Most likely time, according to PERT (Program evaluation and review technique).

Step-by-step explanation:

PERT is "a statistical tool used in project management" (Program evaluation and review technique (2020), in Wikipedia), and it is commonly used with CPM (Critical Path Method) to manage projects.

Inside PERT, there are different defined times to accomplished an activity in a project, that is:

An optimistic time or minimum time required to accomplished an activity, i.e., if everything goes better than normal, the activity is accomplished before expected.
A pessimistic time, a time quite the opposite to optimistic time.
A most likely time, or a time required to accomplished an activity if everything goes as expected or normally.
An expected time, an statistical estimation.

Considering the question, we have that the time when "the first module of the project could be completed":

"[...] in as few as 15 days" is the optimistic time.
"[...] or could take as many as 25 days" is the pessimistic time.
"[...] but most likely will require 20 days" is the most likely time.

As a result, the 20-day estimate is called the most likely time in the context of the PERT/CPM techniques.

3 0

2 years ago