For this reaction: ΔG⁰>0.
Balanced chemical reaction A(g) ⇌ (g)
ΔG° indicates that all reactants and products are in their standard states.
ΔG° = R·T·lnK.
ΔG° is Gibbs free energy
T is the temperature on the Kelvin scale
R is the ideal gas constant
The equilibrium constant (K) is the ratio of the partial pressures or the concentrations of products to reactants.
Gibbs free energy (G) determines if reaction will proceed spontaneously, nonspontaneously or in equilibrium processes.
If K < 1, than ΔG° > 0.
Reactants (in this example A) are favored over products (in this example B) at equilibrium.
More about equilibrium: brainly.com/question/25651917:
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Answer:
mass of CH4 = 14
Molecular mass of CH4 16.04gmol
No of mole of CH4 = 14/16.04
No of mole of CH4 = 0.8728mol
Stoichiometrically, from the above
2 Molecules of Hydrogen will produce 1molecule of methane
Therefore, 2*0.8728 mole of Hydrogen will produce 0.8728mol of Methane.
The no of molecule of hydrogen is 1.7456
If 0.400 moles CO and 0.400 moles O2 completely react, 17.604 grams of CO2 would be produced.
First, let us look at the balanced equation of reaction:

According to the equation, the mole ratio of CO and O2 is 2:1. But in reality, the mole ratio supplied is 1:1. Thus, CO is the limiting reactant while O2 is in excess.
Also from the equation, the ratio of CO consumed to that of CO2 produced is 1:1. Thus, 0.400 moles of CO2 would also be produced from 0.400 moles of CO.
Recall that: mole = mass/molar mass
Therefore, the mass in grams of CO2 that would be produced from 0.400 moles can be calculated as:
Mass = mole x molar mass
= 0.400 x 44.01
= 17.604 grams
More on calculating mass from number of moles can be found here: brainly.com/question/12513822
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