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wlad13 [49]
3 years ago
14

You place a pan of water on the stove and turn on the heat. The water begins to boil. What is happening?

Chemistry
1 answer:
Romashka [77]3 years ago
8 0
The molecules inside of the water start to move around more rapidly which will cause the water to boil
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How many moles are present in a 5.8 g sample of copper?
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Explanation:

Molar mass of Cu = 63.5g/mol

Moles of Cu

= 5.8g / (63.5g/mol) = 0.091mol (B)

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2 years ago
What are three of Leonardo divinci's contributions to science?
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Identify the functional groups present in each molecule.
Colt1911 [192]

Answer:

Carbon 3 is double bonded to an oxygen and attached to carbon 2 and carbon 4. :

Answer: Carbonyl group ( Ketone or aldehyde)

Carbon 17 is attached to an oxygen, which is attached to a hydrogen. :

Answer: Carboxyl group (Carboxylic acid)

A central carbon is attached to an amine, two hydrogens, and a carbon that is double bonded to an oxygen and single bonded to an oxygen attached to a hydrogen. :

Answer: Amide group

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5 0
3 years ago
Given the following information, what is the concentration of H2O(g) at equilibrium? [H2S](eq) = 0.671 M [O2](eq) = 0.587 M Kc =
MAVERICK [17]

<u>Answer:</u> The equilibrium concentration of water is 0.597 M

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For a general chemical reaction:

aA+bB\rightleftharpoons cC+dD

The expression for K_{eq} is written as:

K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

The concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

2H_2S(g)+O_2(g)\rightleftharpoons 2S(s)+2H_2O(g)

The expression of K_c for above equation is:

K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}

We are given:

[H_2S]_{eq}=0.671M

[O_2]_{eq}=0.587M

K_c=1.35

Putting values in above expression, we get:

1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}

[H_2O]=\sqrt{(1.35\times 0.671\times 0.671\times 0.587)}=0.597M

Hence, the equilibrium concentration of water is 0.597 M

8 0
3 years ago
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