Answer:
75603.86473 K
Explanation:
Given that:
The 1st excited electronic energy level of He atom = 3.13 × 10⁻¹⁸ J
The objective of this question is to estimate the temperature at which the ratio of the population will be 5.0 between the first excited state to the ground state.
The formula for estimating the ratio of population in 1st excited state to the ground state can be computed as:
From the above equation:
Δ E = energy difference = 3.13 × 10⁻¹⁸ J
k = Boltzmann constant = 1.38 × 10⁻²³ J/K
Thus:
T = 75603.86473 K
Answer: 48.95g
Explanation:
no. of moles of Cl2 = 39/(2*35.5) = 0.55 mol
no. of moles of Al = 34/27 = 1.26 mol
hence, aluminium is in excess so we'll do calculation using no. of moles of Cl2 as it will be the only reactant to be used up completely. So,
no of moles of AlCl3 = 2/3 * (0.55) = 0.367 mol
hence amount of AlCl3 = 0.367 * (27+3*35.5) = 48.95g
Answer:
6.49g
Explanation:
Let's consider the balanced reaction for photosynthesis.
6 CO₂ + 6 H₂O = C₆H₁₂O₆ + 6 O₂
We can establish the following relations:
- 1 mole of CO₂ has a mass of 44.01 g (MW 44.01)
- The molar ratio of CO₂ to C₆H₁₂O₆ is 6:1.
- 1 mole of C₆H₁₂O₆ has a mass of 180.16 g/mol.
The mass of glucose produced by the reaction of 9.51 g of carbon dioxide is:
Answer: 1, magnesium & mg
2, two energy shells
Explanation:
