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3 years ago

How do you know that Al(OH)3(s) is a base?

Chemistry

2 answers:

TiliK225 [7]3 years ago

8 0

It has an incredibly high pH, and anything above 7 on the pH scale is a base

kirill115 [55]3 years ago

3 0

Explanation:

Bases are those substance which releases hydroxide ions in aqueous solution when dissolved in water.

$BOH(aq)\rightarrow B^+(aq)+OH^-(aq)$

As we can see that in formula of aluminium hydroxide , there are 3 hydroxide ions attached to single aluminum ion. So, when we will dissolve the aluminum hydroxide in water it will give aluminum ions and hydroxide ions in its solution.

$Al(OH)_3(aq)\rightarrow Al^{3+}(aq)+3OH^-(aq)$

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The energy transfer between the system and the surroundings, in the form of heat at constant pressure is described by which of t

kicyunya [14]

I think the answer would be d but not 100% sure

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3 years ago

A sample of krypton gas in a container of volume 1.90 L exerts a pressure of 0.553 atm at 21 Celsius. How many moles of gas are

NeTakaya

Explanation:

pv = nRT

n= PV/RT

n =0.553×1.90/0.0821×294

n=1.0507/24.1374

n=0.0435mol

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3 years ago

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Harman [31]

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2 years ago

The general equation for an acid base reaction looks lik:

pickupchik [31]

Answer

B. acid + base --> salt + water

Explanation

Acids are substances that dissolve in water to produce hydrogen ions, H+.A base is a substance that dissolves in water to produce hydroxide ions, OH-.In a chemical reaction of an acid and a base, the products are a salt and water.For example when hydrocholoric acid is added to sodium hydroxide, a salt namely sodium chloride is formed with additional water.

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3 years ago

Read 2 more answers

Find the ph of of 100 ml of an aqueous 0.43m baoh2 solution

denpristay [2]

Answer is: pH of barium hydroxide is 13.935.
Chemical dissociation of barium hydroxide in water:
Ba(OH)₂(aq) → Ba²⁺(aq) + 2OH⁻(aq).
c(Ba(OH)₂) = 0.43 M.
V(Ba(OH)₂) = 100 mL ÷ 1000 mL/L = 0.1 L.
n(Ba(OH)₂) = 0.43 mol/L · 0.1 L.
n(Ba(OH)₂) = 0.043 mol.
From chemical reaction: n(Ba(OH)₂) : n(OH⁻) = 1 : 2.
n(OH⁻) = 0.086 mol.
c(OH⁻) = 0.86 mol/L.
pOH = -logc(OH⁻).
pOH = 0.065.
pH = 14 - 0.065 = 13.935.

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2 years ago