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SCORPION-xisa [38]
3 years ago
9

The interactions between water molecules and other non-water molecules through hydrogen bonding is known as ____________________

________.
Chemistry
1 answer:
Svetach [21]3 years ago
5 0

Answer: adhesion

Explanation:

Cohesion is the attraction between similar molecules. Example: Force of attraction between water molecules.

Thus hydrogen bond formed between the molecules of water due to the development of partial negative charge on oxygen and partial positive charge on hydrogen is cohesion.

Adhesion is the attraction between different molecules. Example: Force of attraction between HCl and water.

The hydrogen bond formed between H of HCl and O of water due to developments of partial positive and partial negative charge respectively is adhesion.

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Aluminum has a face-centered cubic unit cell. How many atoms of Al are present in each unit cell
Serjik [45]

Answer:4

Explanation:

As shown in the image attached, a face-centred cubic structure has 8 atoms at the corners and 6 face center atoms.

Each corner atom contributes to eight cell, so per unit cell 1/8 ×8 =1atom

Face center atoms contributes to two unit cells 1/2 × 6=3atoms

Total atoms =3+1=4atoms

Therefore the atoms in Al FCC per unit cell is 4

7 0
3 years ago
Combustion of hydrocarbons such as undecane (C_11H_24) produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Eart
bekas [8.4K]

Answer:

Volume of carbon dioxide is 428.23 L.

Explanation:

Below is the chemical reaction or chemical equation for the combustion of hydrocarbons such as undecane into carbon dioxide.

C_{11}H_{24}(l) + 17O_{2}(g) \to 11CO_{2} (g) + 12H_2O(g)

Here, undecane is in liquid form that reacts with gaseous oxygen (combustion)  and produces carbon dioxide and water as a product in the gaseous form.

The molar mass of undecane = 156.31 g/mol.

\text{Number of moles} = \frac{260g}{156.31g/mol} = 1.66 \ mol.

From the equation, it can be seen that 1 mole of undecane produces 11 moles of carbon dioxide. Therefore, 1.66 mol will produce 18.26 mol of carbon dioxide.

Now find the volume of 18.26 mol of carbon dioxide when the temperature is 13 degrees Celsius and pressure is 1 atm.

V = \frac{nRT}{P} \\

V = \frac{18.26 \times 0.082 \times 286 \ K}{1atm} \\

V = 428.23 \ L

6 0
3 years ago
The reaction A → products is first order. If the initial concentration of A is 0.646 M and, after 72.8 seconds have elapsed, the
mario62 [17]

Answer: 0.00867 moldm-3

Explanation:

Since the reaction is 1st order,

Rate of reaction=∆[A]÷t

0.646-0.0146/72.8= 0.00867

Remember that in a first order reaction, the rate of reaction depends on change in the concentration of only one of the reaction species, A in the problem above.

5 0
3 years ago
I need helppppppp plssssss
Irina-Kira [14]

Answer:

<h3>1)20</h3><h3>2)13</h3><h3>3)82</h3><h3>4)56</h3><h3>5)26</h3><h3>6)1</h3><h3>hope it helps</h3><h3>plzzz mark itas brainliest...</h3><h3> </h3><h3 />

4 0
3 years ago
Answers for both boxes please ​
Elan Coil [88]

Explanation:

\frac{6.900 \times  {10}^{10} }{4.000 \times  {10}^{8} }  \\ 1.725 \times  {10}^{10 - 8} \\ 1.725 \times  {10}^{2}

Hope it will help you :)

3 0
2 years ago
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