Answer:
The work done by the electric field in Figure 1 to move a positive charge q from A, the positive plate, higher potential, to B, the negative plate, lower potential, is
W = −ΔPE = −qΔV.
The potential difference between points A and B is
−ΔV = −(VB − VA) = VA − VB = VAB.
Entering this into the expression for work yields W = qVAB.
Work is W = Fd cos θ; here cos θ = 1, since the path is parallel to the field, and so W = Fd. Since F = qE, we see that W = qEd. Substituting this expression for work into the previous equation gives qEd = qVAB.
The charge cancels, and so the voltage between points A and B is seen to be
{
V
AB
=
E
d
E
=
V
AB
d
(uniform E − field only)
Step-by-step explanation:
The relationship between V and E for parallel conducting plates is E=Vd E = V d. From a physicist's point of view, either ΔV or E can be used to describe any charge distribution
Step-by-step explanation:
Science book weighs = 2 1/2 = 2.5 pounds
Library books weigh = 3/8 = 0.375 pounds
Math book weighs = 2.5 ÷ 2 = 1.25 pounds
Total weight of the books = 2.5 + 0.375 + 1.25 = 4.125 pounds
X<12
<span>5(x+5)<85 </span>
<span>5(x + 5)/5 < 85/5 </span>
<span>x + 5 < 17 </span>
<span>x + 5 - 5 < 17 - 5</span>
Answer:
stoopid
Step-by-step explanation:
Answer: the system of equations are
3x + y = 14
y = 4x
Step-by-step explanation:
Let x represent the number of three point shots that Hailey made.
Let y represent the number of free throws(worth one point each) that Hailey made.
Hailey made some three point shots and some free throws and
scored a total of 14 points. This would be expressed as
3x + y = 14
Hailey made 4 times as many free throws as three point shots. This would be expressed as
y = 4x