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gogolik [260]
2 years ago
9

Work out

Mathematics
2 answers:
ycow [4]2 years ago
6 0
Answer 1 or 9/9


Explanation: First we need to find a common denominator which the easiest would be nine and then multiply those to equal nine and then you will get 3/9+6/9 which is equal to 9/9 which reduces to 1 have a nice day (:
trasher [3.6K]2 years ago
5 0

Answer:

The correct answer is 1.

Step-by-step explanation:

In order to solve the problem \frac{3}{9}  + \frac{2}{3}, we need can use two methods.

Method 1: Make the denominators the same.

3/9 + 2/3 =

3/9 + 6/9 =

9/9 =

1

Method 2: Turn both fraction into decimals (<em>by dividing the numerator by the denominator</em>.)

3/9 or 3 ÷ 9 = 0.3 (when rounded to the nearest tenth)

2/3 or 2 ÷ 3 = 0.7 (when rounded to the nearest tenth)

0.3 + 0.7 = 1

Therefore, the answer to this question is 1.

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Charlene wants to earn at least $600 this month in commission. What is the minimum amount she needs to sell to earn $600 if she
nika2105 [10]

Answer:

She will need to earn a little more than $1333 that week.

Step-by-step explanation:

600/0.45 = 1333.333(repeating) rounded to nearest dollar is 1333

Check by doing 1333 x 0.45 (comes out to be 599.85)

3 0
2 years ago
A map of a city uses a scale of 1cm =3.5 meters. If a road shown on the maps runs for 25cm how long is the road?
choli [55]

Answer: 87.5

Step-by-step explanation: 1cm x 25cm = 87.5

5 0
3 years ago
Read 2 more answers
(1 - 5q ) +2 (2.5q +8 )
VikaD [51]
Distribute
remember
a(b+c)=ab+ac
2(2.5q+8)=2(2.5q)+2(8)=5q+16

1-5q+5q+16
1+0+16
17
5 0
3 years ago
A group of four components is known to contain two defectives. An inspector tests the components one at a time until the two def
Stells [14]

Answer:

when Y = 2, P(2) = 1/6 = 0.167

when Y = 3, P(3) = 2/6 = 0.333

when Y = 4, P(4) = 3/6 = 0.5

Step-by-step explanation:

Total number of possible ways to choose 2 components for defectives out of 4 components = 4C2 = 6

Y can only take values of 2, 3 and 4

So, Probability of Y = P(Y) = 1C(Y-1) / 6

when Y = 2, P(2) = 1/6 = 0.167

when Y = 3, P(3) = 2/6 = 0.333

when Y = 4, P(4) = 3/6 = 0.5

4 0
3 years ago
Find the surface area of x^2+y^2+z^2=9 that lies above the cone z= sqrt(x^@+y^2)
Mashcka [7]
The cone equation gives

z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2

which means that the intersection of the cone and sphere occurs at

x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92

i.e. along the vertical cylinder of radius \dfrac3{\sqrt2} when z=\dfrac3{\sqrt2}.

We can parameterize the spherical cap in spherical coordinates by

\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle

where 0\le\theta\le2\pi and 0\le\varphi\le\dfrac\pi4, which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is \dfrac3{\sqrt2}. So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4

Now the surface area of the cap is given by the surface integral,

\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du
=\displaystyle\int_{u=0}^{u=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}9\sin v\,\mathrm dv\,\mathrm du
=-18\pi\cos v\bigg|_{v=0}^{v=\pi/4}
=18\pi\left(1-\dfrac1{\sqrt2}\right)
=9(2-\sqrt2)\pi
3 0
3 years ago
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