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3 years ago

10

a car moving at a soeed of 65km/h starts to accelebrate at a rate of 80km/h. How many minutes does it take for the car to achiev

e a speed of 85km/h

1 answer:

Wittaler [7]3 years ago

4 0

It would take under minutes it would take seconds please forgive me if this is wrong :(

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Marcy is taking part in a summer movie club. She will earn 3 points for each movie she attends throughout the summer. Which equa

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The answer is a \large y=3x

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3 years ago

The sides of a square are increased by a scale factor of 6. The perimeter of the smaller square is 10 ft. What is the perimeter

inn [45]

Answer:

60ft

Step-by-step explanation:

I have not done this kind of work in a while but if you scale each side of the square by 6 is should increase to a perimeter of 60ft

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2 years ago

The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth

Art [367]

Answer:

a) $N_0=250\; k=0.15$

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies $t=0$ . And $N(0)=N_0$ . The process is:

$N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250$

b) After 2 days means $t=48$ . So, we just replace and operate:

$N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}$

c) $N(t_1)=4000; \;t_1=?$

$N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\ \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h$

d) $t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)$

$N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h$

6 0

3 years ago

Tell whether the angles are adjacent or vertical. Then find the value of x.

krok68 [10]

Answer : The angles are vertical angles and the value of x is $25^o$

Step-by-step explanation :

Adjacent angles : It is defined as the two angles that have the common arm and common vertex.

Vertical angles : It is defined as the two lines intersect each other and form angles. The opposite angles are known as vertically opposite angles.

And we know that the vertically opposite angles are equal.

In the given image, the angles are vertical angles and vertically opposite angles are equal.

So,

$(4x-25)^o=75^o$

$4x-25^o=75^o$

$4x=75^o+25^o$

$4x=100^o$

$x=\frac{100^o}{4}$

$x=25^o$

Therefore, the angles are vertical angles and the value of x is $25^o$

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2 years ago

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Helga [31]

Answer:

'

Step-by-step explanation:

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2 years ago