Answer:
x^2 +6x +10xi -16 +30i
Step-by-step explanation:
(x + (3+5i))^2
Rewriting as
(x + (3+5i)) (x + (3+5i))
Let 3+5i = m
(x + m) (x + m)
FOILing
x^2 + xm+xm+m^2
x^2 +2xm + m^2
Replacing m with 3+5i
x^2 +2x (3+5i) +(3+5i)^2
Distribute
x^2 +6x +10xi +(3+5i)^2
Now FOIL (3+5i)^2
( 3+5i) ( 3+5i)
3*3+ 3*5i + 3*5i+ 25i^2
= 9 +15i+15i +25(-1)
9+30i -25
-16 +30 i
Replacing that in the equation
x^2 +6x +10xi -16 +30i
Answer: 0.7257
Step-by-step explanation:
Given : The weights of steers in a herd are distributed normally.
Standard deviation :
Let x be the weight of the randomly selected steer .
Z-score :
The the probability that the weight of a randomly selected steer is greater than 920 lbs using standardized normal distribution table :
Hence, the probability that the weight of a randomly selected steer is greater than 920lbs =0.7257
Answer:
sihhhhjjjjuuuuuuuuuuuuuuii
Factoring out x
x(-3x^2+15x+42) now factor parenthetical expression
x(-3x^2+21x-6x+42)
x(-3x(x-7)-6(x-7))
x(-3x-6)(x-7) we can factor out -3 from first parentheses
-3x(x+2)(x-7)