For this case we have the following functions:
![f (x) = x ^ 2\\g (x) = 2x](https://tex.z-dn.net/?f=f%20%28x%29%20%3D%20x%20%5E%202%5C%5Cg%20%28x%29%20%3D%202x)
If we want
then:
![x ^ 2 = 2x\\x ^ 2-2x = 0](https://tex.z-dn.net/?f=x%20%5E%202%20%3D%202x%5C%5Cx%20%5E%202-2x%20%3D%200)
We take common factor x:
![x (x-2) = 0](https://tex.z-dn.net/?f=x%20%28x-2%29%20%3D%200)
Thus, the values of x that make equality equal are:
![x_ {1} = 0\\x_ {2} = 2](https://tex.z-dn.net/?f=x_%20%7B1%7D%20%3D%200%5C%5Cx_%20%7B2%7D%20%3D%202)
Thus, the values of x for which
are 0 and 2.
ANswer:
The values of x for which
are 0 and 2.
Answer:
x(x + 1)
Step-by-step explanation: This is an important way of solving quadratic equations. The first step of factorising an expression is to 'take out' any common factors which the terms have. So if you were asked to factorise x² + x, since x goes into both terms, you would write x(x + 1)
You would do, 4,200 over 8,000 equals x over 500,000 and then
x*8000=4200*500000
8000 = 2100000000
divide
x= 262500
262500 people
To simplify to their equation on <span>3(x+1)+9 and the answer is =3x+12.
Answer will be bolded.
Have a great day.
-Charlie</span>