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marshall27 [118]
4 years ago
9

How many terms are in x + 8 - 4x^3 ? ( is it 3 ? )

Mathematics
1 answer:
GaryK [48]4 years ago
6 0

Yea I think (leicjjyxhejiwudhfbby)

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The price of gas last summer was $3.80 and this summer it is $1.90. What is the percent of decrease.
Marianna [84]
It was a 50% decrease.
7 0
4 years ago
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If the graph f(x)= 9x^2+37x+41/3x+5 has an oblique asymptote at y=3x+k what is the value of k
ira [324]

Answer:

k=\frac{22}{3}

Step-by-step explanation:

The oblique asymptote of

f(x)=\frac{9x^2+37x+41}{3x+5},

We perform the long division as shown in the attachment.

The quotient is;

3x+\frac{22}{3}

Comparing to 3x+k

Hence the value of k is \frac{22}{3}

6 0
4 years ago
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11. Charles's Law states that at constant pressure, the volume of a fixed amount of gas varies
Zanzabum

Answer:

a.V=5/6T

b. 350 ml

Step-by-step explanation:

a.

V∝T

or V=kT

where k is a constant.

V=250 ml

T=300° K

250=300 k

k=250/300=5/6

so V=5/6 T

b.

V=5/6 T

=5/6×420

=5×70

=350 ml

6 0
3 years ago
Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.â  Suppose a small group of 11 Allen's humming
alexira [117]

Answer:

3.15-1.28\frac{0.38}{\sqrt{11}}=3.003    

3.15+ 1.28\frac{0.38}{\sqrt{11}}=3.297    

So on this case the 80% confidence interval would be given by (3.003;3.297)

And the margin of error is given by:

ME = 1.28\frac{0.38}{\sqrt{11}}= 0.147    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=3.15 represent the sample mean

\mu population mean (variable of interest)

\sigma=0.38 represent the population standard deviation

n=11 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.80 or 80%, the value of \alpha=0.2 and \alpha/2 =0.1, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NOR.INV(0.1,0,1)".And we see that z_{\alpha/2}=1.28

Now we have everything in order to replace into formula (1):

3.15-1.28\frac{0.38}{\sqrt{11}}=3.003    

3.15+ 1.28\frac{0.38}{\sqrt{11}}=3.297    

So on this case the 80% confidence interval would be given by (3.003;3.297)

And the margin of error is given by:

ME = 1.28\frac{0.38}{\sqrt{11}}= 0.147    

8 0
3 years ago
Find the quotient. 28,134 ÷ 47
Marizza181 [45]

Answer:

28,134 / 47 = 598.6

Step-by-step explanation:

8 0
3 years ago
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