A traveler is walking on a moving walkway in an airport The Traveler must walk back on the walkway to get a bag he forgot the Tr
avelers ground speed is 2ft/s against the walkway and 6ft/s with the walkway what is the Travellers speed off the walkway what is the speed of the moving walkway
Let the speed off the walk way be x and speed of the walkway be y x+y=6....i x-y=2....ii adding the above equation we get: 2x=8 thus x=4 ft/s and y=6-4=2 ft/s thus the speed off the walk way is 4 ft/s the speed of the moving walkway is 2 ft/s
You can first multiply your coefficients (7x9), which gives you 63. You can then simplify the exponents by using the rule that when two terms with the same variable are being multiplied, you can simplify by adding exponents. Since 7+3= 10, your simplified answer would be 63x^10 :) hope it helped!
