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kozerog [31]
3 years ago
8

2/7 equilvlent ratio

Mathematics
1 answer:
vampirchik [111]3 years ago
3 0

Answer:

Any from 1:3.5 , 4:14 , 6:21 (etc) would be equal to 2:7

Step-by-step explanation:

2 divided by 2 would be 1, and 7 divided by 2 would be 3.5. 2 times 2 = 4, and 7 times 2 = 14. 2 x 3 = 6, 7 x 3 = 21 (etc).

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If a watch has a 0.12 defect rate. what is the probability that the watch has fewer than 3 defects in a run of 75 chimes?
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Answer:

(\frac{88}{100})^{75} + \binom{75}{1} (\frac{88}{100})^{74}(\frac{12}{100}) + \binom{75}{2} (\frac{88}{100})^{73}(\frac{12}{100})^{2}

Step-by-step explanation:

If a watch has fewer than three defects, then either 1.) It has no defects, 2.) it has exactly 1 defect, or 3.) it has exactly 2 defects.

1.) The probability that the watch has no defects is (\frac{88}{100})^{75}, because for every chime there is a probability of \frac{88}{100} that there is no defect

2.) The probability that the watch has exactly 1 defect is (\frac{88}{100})^{74}(\frac{12}{100}) times the number of ways you can choose 1 of 75 of the chimes to be defective, which is \binom{75}{1}, so the probability that the watch has exactly 1 defect is \binom{75}{1} (\frac{88}{100})^{74}(\frac{12}{100}).

3.) For the same reason as 2.), the probability that the watch has exactly two defects is \binom{75}{2} (\frac{88}{100})^{73}(\frac{12}{100})^{2}

Since 1.), 2.), and 3.) are mutually exclusive events, the probability of their union is simply the probability of each of them added together, which is (\frac{88}{100})^{75} + \binom{75}{1} (\frac{88}{100})^{74}(\frac{12}{100}) + \binom{75}{2} (\frac{88}{100})^{73}(\frac{12}{100})^{2}

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Step-by-step explanation:

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