Answer:
the probability that a randomly chosen test-taker will score 142 or lower = 0.8643
Step-by-step explanation:
We are given;
Data point; x = 142
Mean; μ = 153
Standard deviation; σ = 10
So,let's find the z-score using;
z = (x - μ)/σ
z = (142 - 153)/10
z = -1.1
From the z-distribution table attached, the probability is;
P(z < -1.1) = 1 - 0.13567 ≈ 0.8643
Answer:
The required equation for the amount of Simple Internet =
Step-by-step explanation:
Here , Principal amount = $450,000
Time = 1 year
Rate of Interest = 3.5%
Now,SIMPLE INTEREST =
So, here SI =
Hence, the required equation for the amount of Simple Internet =
Answer:
4/27=14.8%
Step-by-step explanation:
In order to solve this, we have to see first each option possible, there are 2/3 of possibilities that a random Entrée ends up being Chicken Cutlet or Lasagna, then you have again 2/3 chances to get milk or water, and as you only want fruit the chances are 1/3 that you get that.
In order to calculate if this could happen at random we have to multiply all of the odds:
So we know that for every 27 times you pick a lunch at random, 4 times it will not have the Veggie Wrap, contain milk or water, and will have fruit as the snack.