Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.
Step-by-step explanation:
Salt in the tank is modelled by the Principle of Mass Conservation, which states:
(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)
Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

By expanding the previous equation:

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

Since there is no accumulation within the tank, expression is simplified to this:

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:
, where
.

The solution of this equation is:

The salt concentration after 8 minutes is:

The instantaneous amount of salt in the tank is:
For problem 2:
The answer would be B) Car A travels more miles per gallon of fuel than Car B.
This is because Car B is shown on the graph to travel the same number of miles as Car A using 16 gallons of fuel, while Car A uses only 4 gallons. Thus, Car A travels further with less fuel.
For problem 3:
Let's write out the equation and try to solve.
5x + 1 = 3x + 7
First, subtract 3x from both sides.
5x - 3x + 1 = 3x - 3x + 7
2x + 1 = 7
Now, subtract one from both sides.
2x + 1 - 1 = 7 - 1
2x = 6
Finally, divide both sides by 2.
2x/2 = 6/2
x = 3
You should only get B) One solution
Hope that helped!
2.78 that will be the awnser if you go gor it
Answer:
rectagular
Step-by-step explanation:
Answer:
lim(x---->0) = -5
Step-by-step explanation:
first: sin(x-π/2)= -cosx
so the equation will be :
lim(x---->0) = [-6cos(ax)-1}/cosx
solve :
lim(x---->0) = [-(6cos(a(0))-1}/cos(0)
cos0=1
lim(x---->0)=(-(6(1)-1)/1
lim(x---->0)=-6+1/1
lim(x---->0)=-5