Answer:
a) CI = ( 5,1 ; 5,7 )
b) SE = 0,1
Step-by-step explanation:
a) Sample random n = 100
Mean = μ = 5,4
Standard deviation s = 1,3
CI = 99 % α = 1 % α = 0,01 α/2 = 0,005
z(c) for 0,005 is from z-table z(c) = 2,575
z(c) = ( X - μ ) /s/√n CI = μ ± z(c) * s/√n
CI = 5,4 ± 2,575* 1,3/10
CI = 5,4 ± 0,334
CI = ( 5,1 ; 5,7 )
b) SE = Standard deviation / √n
SE = 1,3 /10 SE = 0,1
We can support that with 99 % of probability our random variable will be in the CI.
Answer:
0.395 kilometre
Step-by-step explanation:
Given:
On Martin's first stroke, his golf ball traveled 4/5 of the distance to the hole.
On his second stroke, the ball traveled 79 meters and went into the hole.
<u>Question asked:</u>
How many kilometres from the hole was Martin when he started?
<u>Solution:</u>
Let distance from Martin starting point to the hole in meters = 
On Martin's first stroke, ball traveled = 

On his second stroke, the ball traveled and went to the hole = 79 meters
Total distance from starting point to the hole = Ball traveled from first stroke + Ball traveled from second stroke

Now, convert it into kilometre:
1000 meter = 1 km
1 meter = 
395 meters = 
Thus, there are 0.395 kilometre distance from Martin starting point to the hole.
9^1/3 * 3^x = 27^4/5
Rewrite 9 as 3^2
(3^2)^1/3 * 3^x = 27^4/5
Multiply the exponents in the first term:
3^2/3 * 3^x = 27^4/5
Use power rule to combine exponents:
3^(2/3 +x) = 27^4/5
Rewrite the 2nd term:
3^(2/3 +x) = (3^3)^4/5
Set the exponents only to equal:
2/3 + x = 3(4/5)
Solve for x:
simplify the right side:
2/3 + x = 12/5
Subtract 2/3 from both sides:
x = 26/15
Answer:
the correct answer is d.
Step-by-step explanation:
i hope this helps :)
Answer:
Step-by-step explanation:
12 multiplied by 9 is 108. That gives us the square. The triangle base is 9. The height is 7. 7 multiplied by 9 is 63. 63 divided by 2 is 31.5. 108 add 31.5 is 139.5 cm squared.