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VladimirAG [237]
3 years ago
13

A 0.200 kg block on a vertical spring with spring constant of 4.65 ✕ 103 N/m is pushed downward, compressing the spring 0.084 m.

When released, the block leaves the spring and travels upward vertically. How high does it rise above the point of release?
Physics
1 answer:
vlada-n [284]3 years ago
4 0

Answer:

PEel = PEg

PEel = .5 * k * x^2

= .5 * 4650 * .1^2

= 23.25

PEg= m * g * h

=.2 * 9.81 * h

23.25 = 1.962* h

h = 11.85

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alisha [4.7K]

Answer:

Q = 5 L/s

Explanation:

To find the flow you use the following formula (para calcular el caudal usted utiliza la siguiente formula):

Q=\frac{V}{t}

V: Volume (volumen) = 200L

t: time (tiempo) = 40 s

you replace the values of the parameters to calculate Q (usted reemplaza los valores de los parámteros V y t para calcular el caudal):

Q=\frac{200L}{40s}=5\frac{L}{s}

Hence, the flow is 5 L/s (por lo tanto, el caudal es de 5L/s)

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The answer ro this question is fear of failure

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The object of badminton is to hit the birdie or "shuttlecock" over the net and onto to court to score how many points to win gam
xxTIMURxx [149]

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3 years ago
n 38 g rifle bullet traveling at 410 m/s buries itself in a 4.2 kg pendulum hanging on a 2.8 m long string, which makes the pend
Kitty [74]

Answer:

68cm

Explanation:

You can solve this problem by using the momentum conservation and energy conservation. By using the conservation of the momentum you get

p_f=p_i\\mv_1+Mv_2=(m+M)v

m: mass of the bullet

M: mass of the pendulum

v1: velocity of the bullet = 410m/s

v2: velocity of the pendulum =0m/s

v: velocity of both bullet ad pendulum joint

By replacing you can find v:

(0.038kg)(410m/s)+0=(0.038kg+4.2kg)v\\\\v=3.67\frac{m}{s}

this value of v is used as the velocity of the total kinetic energy of the block of pendulum and bullet. This energy equals the potential energy for the maximum height reached by the block:

E_{fp}=E_{ki}\\\\(m+M)gh=\frac{1}{2}mv^2

g: 9.8/s^2

h: height

By doing h the subject of the equation and replacing you obtain:

(0.038kg+4.2kg)(9.8m/s^2)h=\frac{1}{2}(0.038kg+4.2kg)(3.67m/s)^2\\\\h=0.68m

hence, the heigth is 68cm

4 0
3 years ago
What velocity must a car with a mass of 1110 kg have in order to have the same momentum as a 2280 kg pickup truck traveling at 2
shutvik [7]

Answer:

49.3 m/s

Explanation:

The momentum is defined as the product of the object velocity and its mass.

So the momentum of the truck is

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For the car to have the same momentum, its speed must be

v_c = P_t/m_c = 54720 / 1110 = 49.3 m/s

6 0
4 years ago
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