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Roman55 [17]
2 years ago
10

13. in batesian mimicry, a palatable species gains protection by mimicking an unpalatable one. imagine that individuals of a pal

atable, brightly colored fly species are blown to three remote islands. the first island has no predators of that species; the second has predators but no similarly colored, unpalatable species; and the third has both predators and a similarly colored, unpalatable species. in a short essay (100-150 words), predict what might happen to the coloration of the palatable species on each island through evolutionry time if coloration is a genetically controlled trait. explain your predictions.
Physics
1 answer:
fiasKO [112]2 years ago
6 0

Batesian mimicry is an adaptive feature associated with the coloration of a given species in a given environment.

<h3>What is Batesian mimicry?</h3>

Batesian mimicry can be defined as a type of adaptive feature associated with the coloration of a particular species and/or population.

On the first island, the color of the population won't change because of the absence of predators.

On the second island, the color of the population will change because of the presence of predators that can be alerted by the color.

On the third island, the color of the population won't change because of the presence of a species with a similar color.

In conclusion, Batesian mimicry is an adaptive feature associated with the coloration of a given species in a given environment.

Learn more about Batesian mimicry here:

brainly.com/question/14139071

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jolli1 [7]
The answer is 52.79 m.

I used this formula to get the formula for Vy:
v^2=vi^2+2(a)(x)
And got
Vy=square root (19.6 h)

Then I used that and put it in this formula:

tan(65) =Vy/Vx

tan(65) = square root (19.6 h)/15.0

Then I rearranged it to:

h=[(15.0)(tan65)]/19.6

h=52.79 m
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What is the information gathered in an investigation is called
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1. You serve a volleyball with a mass of 2.1kg. The ball leaves your
Darina [25.2K]

The kinetic energy is 945 joules.

Kinetic energy is the energy that an object has as a result of motion. It is defined as the effort required to accelerate a mass-determined body from rest to the indicated velocity.

The speed of an object or particle, which is a scalar quantity, is the size of the change in its location over time or the size of the change in its position per unit of time.

The mass of the volleyball is 2.1 kg.

The speed of the ball when the ball leaves the hand is 30 m/s.

m = 2.1 kg

v = 30 m/s

The kinetic energy of an object is given as:

KE = (1/2 ) × m × v²

KE = (1 / 2) × 2.1 kg × ( 30 m/s)²

KE = (1 / 2) × 2.1 kg × 30 m/s × 30 m/s

KE = 2.1 kg × 15 m/s × 30 m/s

KE = 945 J

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6 0
1 year ago
A pot on the stove contains 200 g of water at 20°C. An unknown mass of ice that is originally at −10°C is placed in an identical
Mumz [18]

Answer:

a) The mass of the ice is smaller than the mass of the water

b) The ice reaches first 80°C ,

Explanation:

Since the heat Q that should be provided to ice

Q = sensible heat to equilibrium temperature (as ice) + latent heat + sensible heat until final temperature ( as water)

m ice * c ice * ( T equil -T initial  ) + m ice* L + m ice* c water * ( T final - T equil)

and the heat Q that should be provided to water is

Q= m water * c water * ( T final - T equil )

since the rate of heat addition q = constant and the time t taken to reach the final temperature is the same , then the heat absorbed Q=q*t is the same for both, therefore

m water * c water *  ( T final - T equil ) = m ice* [c ice *( T equil -T initial  ) + L + c water * ( T final - T equil)]

m water/ m ice =  [c ice * ( T equil -T initial  )  + L + c water * ( T final - T equil)]/ [ c water * ( T final - T equil)]

m water/ m ice = [c ice * ( T equil -T initial  )  + L ]/[c water * ( T final - T equil) ] + 1

since  [c ice * ( T equil -T initial  )  + L ]/[c water * ( T final - T equil) ] >0 , then

m water/ m ice > 1

m water > m ice

so the mass of ice is smaller that the mass of water

b) Since the heat Q that should be provided to the ice, starting from 55°C mass would be

Q ice= m ice * c water * ( T final2 - T final1 )

and for the water mass

Q water = m water * c water * ( T final2 - T final1 )

dividing both equations

Q water / Q ice = m water / m ice >1

thus

Q water > Q ice

since the heat addition rate is constant

Q water = q* t water and Q ice=q* t ice

therefore

q* t water > q* t ice

t water >  t ice

so the time that takes to reach 80°C is higher for water , thus the ice mass reaches it first.

5 0
3 years ago
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