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Goshia [24]
4 years ago
13

The person has an upward acceleration of 0.70 m/s^2 and is lifted from rest through a distance of 13 m. A rescue helicopter lift

s a 80-kg person straight up by means the cable? (a) What is the tension in the cable? (b) How much work is done by the tension in the cable? (c) How much work is done by the person's weight? (d) Use the work-energy theorem and find the final speed of the person.
Physics
1 answer:
Alex4 years ago
6 0

Answer:

a)

840 N

b)

10920 J

c)

- 10192 J

d)

4.3 m/s

Explanation:

a)

T = tension force in the cable in upward direction = ?

a = acceleration of the person in upward direction = 0.70 m/s²

m = mass of the person being lifted = 80 kg

Force equation for the motion of person in upward direction is given as

T - mg = ma

T = m (g + a)

T = (80) (9.8 + 0.70)

T = 840 N

b)

d = distance traveled in upward direction = 13 m

W_{t} = Work done by tension force

Work done by tension force is given as

W_{t} = T d

W_{t} = (840) (13)

W_{t} = 10920 J

c)

d = distance traveled in upward direction = 13 m

W_{g} = Work done by person's weight

Work done by person's weight is given as

W_{g} = - mg d

W_{g} = - (80 x 9.8) (13)

W_{g} = - 10192 J

d)

F_{net} = Net force on the person = ma = 80 x 0.70 = 56 N

v₀ = initial speed of the person = 0 m/s

v = final speed

Using work-energy theorem

F_{net} d = (0.5) m (v² - v₀²)

(56) (13) = (0.5) (80) (v² - 0²)

v = 4.3 m/s

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tino4ka555 [31]

Answer:

2\ ly=1.89\times 10^{16}\ m

Explanation:

The question says that, "The closest star to the earth is 2 light years away. Calculate this distance in SI units".

Given that,

The distance between the closest star and the Earth is 2 light years.

The SI unit of distance is m. It means we need to convert light years to meters. We know that,

1\ ly=9.461\times 10^{15}\ m

2 light-years means,

2\ ly=2\times 9.461\times 10^{15}\ m\\\\=1.89\times 10^{16}\ m

So, the required distance is equal to 1.89\times 10^{16}\ m.

5 0
3 years ago
A person walks in the following pattern: 3.1 km north, then 2.4 km west, and finally 5.2 km south. a) Sketch the vector diagram
zysi [14]

Answer:

d = 3.19 km

direction is given as

\theta = 41.2 degree South of West

Explanation:

Part b)

displacement is given as

d_1 = 3.1 \hat j

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d_3 = 5.2(-\hat j)

now we will have

d = d_1 + d_2 + d_3

d = 2.4 \hat i + (3.1 - 5.2)\hat j

d = 2.4 \hat i - 2.1 \hat j

total displacement is given as

d = \sqrt{2.4^2 + 2.1^2}

d = 3.19 km

direction is given as

tan\theta = \frac{-2.1}{2.4}

\theta = 41.2 degree South of West

3 0
4 years ago
When two sticks are laid end-to-end they cover a length of 8.32 feet. One stick is 2.93 ft longer than the other. What is the le
77julia77 [94]

To solve this problem we will start by defining the length of the shortest stick as 'x'. And the magnitude of the longest stick, according to the statement as

x+2.93

Both cover a magnitude of 8.32 ft, therefore

x +(x+2.97) = 8.32

Now solving for x we have,

x + (x + 2.93) = 8.32

2x + 2.93 = 8.32

2x = 8.32 - 2.93

x = \frac{ 8.32 - 2.93}{2}

x = 2.695 ft

Therefore the shorter stick is 2.695ft long.

7 0
4 years ago
If the momentum of a 1000 kg car travelling at 10 m/s was transferred completely to a 20.0 kg traffic barrier, what would the fi
denis-greek [22]

Answer:

d. 500 m/s

Explanation:

Momentum: This is the product of the mass of a body to its velocity, The S.I unit of momentum is kgm/s.

Mathematically, momentum can be expressed as,

M = mv....................... equation 1

Where M = momentum, m = mass, v = velocity

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Momentum of the car = momentum of the barrier.

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Where M = mass of the car, V = velocity of the car, m = mass of the barrier, v = velocity of the barrier.

making v the subject of the equation,

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Substitute into equation 2

v = 1000(10)/20

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ivann1987 [24]

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% depleted = 2.0/(2.0 + 19) ×100=9.5%

6 0
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