4 years ago

Find a counterexample to the conjecture: Any number that is divisible by 2 is also divisible by 4

1 answer:

6 0

Choose number 2, it is divisible by 2, $2:2=1$ but it is not divisible by 4, because $2:4=0,5$ but $0,5 \notin \mathbb Z$ .

You might be interested in

inn [45]

Everything is in the picture. All transformations are on y so entire functions gets affected

8 0

3 years ago

Sophie [7]

Answer:

Step-by-step explanation:

7 0

3 years ago

ehidna [41]

Answer:

Therefore,

$a_{21}=2$

Step-by-step explanation:

Given:

$A=\left[\begin{array}{ccc}3&6&9\\2&4&8\\\end{array}\right]$

To Find:

a₂₁ = ?

Solution:

Let,

$A=\left[\begin{array}{ccc}a_{11}&a_{12}&a_{13}\\a_{21}&a_{22}&a_{23}\\\end{array}\right]$

We require ' a₂₁ ' i.e Second Row First Column Element

So on Comparing we get

∴ $a_{21}=2$

Therefore,

$a_{21}=2$

5 0

3 years ago

Marta_Voda [28]

Let the integers be x-2, x, x+2.

Given,

x -2 + x + x + 2 = 69

3x = 69

x = 23

Hence, the integers are 21, 23 and 25.

6 0

3 years ago

Lyrx [107]

18 percent of 90 is 16.2

6 0

3 years ago