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3 years ago

If a welder completed 136 out of 160 welds so far, what is the percent of welds that has been completed?

1 answer:

6 0

85%. You take the completed amount and divide it by amount you have in all. Which gives you 136 divided by 160. Which will give you .85 then you move the decimal to give you a percent of 85

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HELP PLEASE! Find the standard deviation for Data set 1 and 2. round to the nearest hundred. DATA SET ONE: 8.2, 11.6 8.7, 10.6,

Elan Coil [88]

Answer:

0.92 and 1.25 respectively

Step-by-step explanation:

0.92 and 1.25 respectively

first the mean of each value which is 9.7 and 9.8 respectively

standard deviation = square root of the mean deviation of each value

then deduct the mean from each element

and square each value and add them together. not you should square each deviation value before you add them

at last divide the result by the number of frequency and find it's square root

3 0

3 years ago

What is the solution to y=12

Nimfa-mama [501]

Answer:

y=12

Step-by-step explanation:

This equation cannot be simplified further.

Hope this helped! :)

8 0

2 years ago

A pack of folders has a length of 5 inches, a width of 12 inches, and a height of 1 inch. The pack of folders will be shipped in

777dan777 [17]

Answer:

A) Each pack of folders has a volume of 60 cubic inches.

B) The box has a volume of about 720 cubic inches

D) If the box help 20 packs of folders, it would have a volume of about 1,200 cubic inches.

Step-by-step explanation:

Verify each statement

A) Each pack of folders has a volume of 60 cubic inches.

The statement is True

Because

The volume of each pack of folders is equal to

$V=(5)(12)(1)=60\ in^{3}$

B) The box has a volume of about 720 cubic inches

The statement is True

Because

The volume of the box is equal to the volume of one pack of folders multiplied by 12

$V=(12)60=720\ in^{3}$

C) If the box held 15 packs of folders, it would have a volume of about 1,200 cubic inches

The statement is False

Because

Applying proportion

$\frac{12}{720}\frac{packs}{in^{3}}=\frac{15}{x}\frac{packs}{in^{3}}\\ \\x=720*15/12\\ \\x=900\ in^{3}$

$900\ in^{3}\neq 1,200\ in^{3}$

D) If the box help 20 packs of folders, it would have a volume of about 1,200 cubic inches.

The statement is True

Because

Applying proportion

$\frac{12}{720}\frac{packs}{in^{3}}=\frac{20}{x}\frac{packs}{in^{3}}\\ \\x=720*20/12\\ \\x=1,200\ in^{3}$

$1,200\ in^{3}= 1,200\ in^{3}$

E) Each pack of folders has a volume of 24 cubic inches.

The statement is False

Because

The volume of each pack of folders is equal to

$V=(5)(12)(1)=60\ in^{3}$

7 0

3 years ago

A quarterback throws an incomplete pass. The height of the football at time t is modeled by the equation h(t) = –16t2 + 40t + 7.

Nostrana [21]

Indicated here when h(t) = 0, we are to find for the time where the football has reached a certain height.

Then, the values of t would be -0.2 and 2.7.

Since we are to look for the time, it is impossible for us to have an answer that has a negative value. So based from our answer, the solution that we will eliminate is the -0.2 one. Since its value is negative.

So, the correct value would be the 2.7 sec. one.

5 0

3 years ago

Read 2 more answers

Find m∠ABD and m∠CBD given m∠ABC = 111∘.

sineoko [7]

Answer:

m∠ABD = 88º

m∠CBD = 23º

Step-by-step explanation:

(-10x + 58) + (6x + 41) = 111

Combine like terms

-4x + 99 = 111

Subtract 99 from both sides

-4x = 12

Divide both sides by -4

x = -3

------------------------

m∠ABD = -10x + 58

m∠ABD = -10(-3) + 58

m∠ABD = = 30 + 58

m∠ABD = 88º

m∠CBD = 6x + 41

m∠CBD = 6(-3) + 41

m∠CBD = -18 + 41

m∠CBD = 23º

7 0

3 years ago

Read 2 more answers