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inessss [21]
3 years ago
11

If phone company needs to know how tall a cell tower is so I decide to use a 2 m pool and shadow cast by the sun as shown in the

diagram below shadows and the point B what is the height of the tower

Mathematics
1 answer:
Montano1993 [528]3 years ago
6 0
Check my math answers, please?<span>1. Lines PL, AE, and RT are all parallel to each other. What is the length of segment LT? 
http://oi47.tinypic.com/27wr5eu.jpg 


a. 14 

b. 7 

c. 8 <<<<<<my answer 

d. 6 
2. A phone company worker needs to know the height of a cell tower, so he decides to use a 3 m pole and shadows cast by the sun, as shown in the diagram. Both shadows end at point B. What is the height of the tower? 
http://oi49.tinypic.com/2d1qouv.jpg 

a. 30 m <<<<<<my answer 

b. 36 m 

c. 45 m 

d. 50 m 
3. What is the length of segment AD? 
http://oi45.tinypic.com/sqs2g0.jpg 

a. 3 

b. 12 

c. 15 <<<<<< my answer 

d. 20 

4.A pair of corresponding sides of two similar pentagons have lengths of 12 cm and 28 cm. What is the ratio of the areas of the two pentagons? 
http://oi46.tinypic.com/2l9jvbn.jpg 

Option A: 12/28 <<<<<my answer 

Option B: 27/343 

Option C: 28/12 

Option D: 9/49 

5. If a dilation transforms pre-image AEB to create image ADC, which is the proper term for point A? 
http://oi45.tinypic.com/2n6u1s8.jpg 

a. contraction point 

b. center of dilation 

c. scale factor <<<<<my answer 

d. pre-image point 

6. A pre-image segment with endpoints (2, -1) and (4, 2) is dilated to the image segment with endpoints (4, -2) and (8, 4). What is the scale factor for the dilation? 
http://oi45.tinypic.com/6q9x5j.jpg 

a. 2 

b. 4<<<<my answer 

c. 6 

d. 8 

7. The volumes of two similar solids are 20 cm^3 and 540 cm^3. Which is the ratio of the corresponding sides of the larger figure to the smaller figure? 

a. 27 

b. 9 

c. 6 

d. 3 
8. On the coordinate plane, the origin is the center of a contraction with a scale factor of p. Which shows the coordinates of the image points for pre-image points (x, y)? 
a. (p + x, p + y) 

b. (x - p, y - p) 

c. (px, py) 

d. (p - x, p - y) <<<<<my answer 
9. Two right triangles are similar. Which of the following must the similar triangles have? 

a. every pair of sides congruent 

b. congruent corresponding angles and proportional side lengths <<<<<my answer 

c. at least one pair of congruent sides 

d. an obtuse angle 

10. The vertices of a pre-image are located at points (-3, 3), (0, 0), and (-2, -1). If the image triangle has vertices with coordinates (9, 9), (0, 0), and (-6, -3), what type of dilation is it? 

a. expansion 

b. contraction 

c. reflection <<<<<my answer 

d. rotation 
11. The diagram shows a 76 m building with a flagpole outside. The shadows of the building and the flagpole end at point C. What is the height of the flagpole? http://oi50.tinypic.com/35lsyl2.jpg 


5.68 m 

12 m 

14.25 m <<<<<<my answer 

518 m 
12. The side lengths of two different cubes are 36 cm and 45 cm. What is the ratio of the volume of the smaller to the volume of the larger (in simplest form)? Note: These cubes are not drawn to scale. 
http://oi46.tinypic.com/359yaom.jpg 

Option A: 4/5 <<<<my answer 

Option B: 12/15 

Option C: 16/25 

Option D: 64/125 

13. Which of the following can be used to prove that the two triangles are similar?http://oi50.tinypic.com/2prbthz.jpg 
SAA Similarity Theorem 

SAS Similarity Theorem <<<<<my answer 

SSA Similarity Postulate 

ASA Similarity Postulate

There you go ;)

</span>
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svetlana [45]
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5 0
3 years ago
Mr Adams worked 78 hours during his six-day work week if he worked the same number of hours every day, how many hours did he wor
Vedmedyk [2.9K]

Answer:

Mr Adams worked for 52 hours in four days.

Step-by-step explanation:

To get 52, you divide 78 and 6 and get 13. 13 is how many hours he worked a day. Since we need to find out how many hours he worked for 4 days, we add 13 4 times. If we add, the equation would look like this: 13+13+13+13=52. We can multiply also since it's easier. If we multiply our equation would be 13×4. Therefore, Mr Adams worked 52 hours in four days. Hope this helped

5 0
3 years ago
A rocket is shot straight up into the air with an initial velocity of 500 ft per second and from a height of 20 feet above the g
iragen [17]

The height of the rocket above the ground after t seconds is given by the equation :  H= -16t^2+Vt+h , where V is the initial velocity and h is the initial height.

Given that, V= 500 ft/second and h= 20 ft

So, the equation will become:  H= -16t^2 +500t+20

A) For finding the height of the rocket 3 seconds after the launch, we will <u>plug t=3 into the above equation</u>. So....

H= -16(3)^2+500(3)+20\\ \\ H= -16(9)+1500+20\\ \\ H= -144+1500+20=1376

So, the height of the rocket 3 seconds after the launch is 1376 feet.

B) When the rocket at a height of 400 feet, then <u>we will plug H= 400</u>

400=-16t^2+500t+20\\ \\ 16t^2-500t-20+400=0\\ \\ 16t^2-500t+380=0\\ \\ 4(4t^2-125t+95)=0\\ \\ 4t^2-125t+95=0

Using quadratic formula, we will get......

t= \frac{-(-125)+/-\sqrt{(-125)^2-4(4)(95)}}{2(4)}\\ \\ t= \frac{125+/-\sqrt{14105}}{8}\\ \\ t= 30.4705... \\ and \\ t= 0.7794...

So, after 0.7794...seconds and 30.4705...seconds the rocket is at a height of 400 feet above the ground.

C) The time duration that the rocket remains in the air means we need to find <u>the time taken by the rocket to reach the ground</u>. When it reaches the ground, then H=0. So.....

0=-16t^2+500t+20\\ \\ -4(4t^2-125t-5)=0\\ \\ 4t^2-125t-5=0

Using <u>quadratic formula</u>, we will get.....

t= \frac{-(-125)+/-\sqrt{(-125)^2-4(4)(-5)}}{2(4)}\\ \\ t= \frac{125+/-\sqrt{15705}}{8}\\ \\ t=31.2899...\\ and\\ t= -0.0399...

<em>(Negative value is ignored as time can't be in negative)</em>

So, the rocket will remain in the air for 31.2899... seconds.

5 0
4 years ago
Which expression is equivalent to 4-(-7)?<br><br> A.7+4 B.4-7 C.-7-4 D.-4+7
umka2103 [35]

the answer would be A. because two negatives equal a positive

7 0
3 years ago
Read 2 more answers
Determine if 9x2 - 42x + 49 can be the area of a square. If so, what would the value of x have to be if the area of the square i
fiasKO [112]
18-42x+49=64
42x=67-64
42x=3
x=3/42
x=1/14or0.0712
7 0
4 years ago
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