Answer:
They are not similar
Step-by-step Explanation:
For two polygons to be considered similar, two conditions must be met:
1. The ratio of their corresponding sides must be equal, and must have the same scale factor.
2. Their corresponding angles must be the same. That is, the corresponding angles must be congruent.
Now let us examine the two polygons ( ∆AYP and ∆BOX) given to ascertain if they are similar.
First, we can observe that only two of their corresponding sides were given. The third corresponding side, "YP/OX" is not given. This makes it difficult for us to tell if the polygons are similar, if we are to base our conclusion on merely considering the ratio of their corresponding sides.
Although, the two given corresponding sides (AY/BO & AP/BX), both have equal ratio ⅖, i.e. AY/BO = AP/BX = ⅖. This is not enough to tell both polygons are similar, as we cannot tell if the third corresponding side would give us same ratio, since it wasn't given in the diagram.
==>Next is to examine the interior angles of the polygons, whether the measure of their corresponding angles are the same.
Thus, from the diagram, we can see that two angles of the each triangle were given. We can find the measure of the third angle not given since we know that sum of the interior angles of a triangle = 180°
Thus, <P in ∆AYP = 180 - (90+20) = 180 - 110
<P = 70°
Thus, <B in ∆BOX = 180 - (90+80) = 180 - 170
<B = 10°
From the above calculation, comparing both polygons having known the measures of their corresponding angles, we can conclude that both polygons given in the question are not similar.
This is because the measure of their corresponding angles are not congruent.
<A is not congruent to <B, so likewise with <P and <X.
