Answer:
ΔG° = -8.8 kJ/mol
Explanation:
The standard Gibbs free energy of reaction (ΔG°) can be calculated using the following expression.
ΔG° = ΔH° - T.ΔS°
where,
ΔH°: standard enthalpy of reaction
T: absolute temperature
ΔS°: standard entropy of reaction
At 298 K (the temperature that is usually used), ΔG° for the hydrolysis of lactose is:
ΔG° = ΔH° - T.ΔS°
ΔG° = 0.44 kJ/mol - 298 K × 0.031 kJ/mol.K
ΔG° = -8.8 kJ/mol
Answer:
153.8 g/mol.
Explanation:
The molar mass of a compound = ∑ atomic masses of atoms.
<em>∴ The molar mass of CCl₄ = 1(atomic masss of C) + 4 (atomic mass of Cl) </em>= (12.0 g/mol) + 4 (35.45 g/mol) = <em>153.8 g/mol.</em>
Answer:
1.395M NaOH
Explanation:
Sodium hydroxide, NaOH, reacts with nitric acid, HNO3, as follows:
NaOH + HNO3 → NaNO3 + H2O
<em>Where 1mol of NaOH reacts with 1mol of HNO3</em>
To solve this question we must find the concentration of the titrant. With the concentration and the needed acid we can find the moles of HNO3 added = moles NaOH in the solution. With the moles of NaOH and its volume we can find its concentration as follows:
<em>HNO3 concentration:</em>
10.00mol/L HNO3 * (125.0mL/500.0mL) = 2.500M HNO3
<em>Moles HNO3 = Moles NaOH:</em>
16.74mL = 0.01674L*(2.500mol/L) = 0.04185 moles HNO3 = Moles NaOH
<em>Concentration NaOH:</em>
0.04185 moles / 0.0300L =
1.395M NaOH
Answer:
D
Explanation:
Because when you combine chemical substances they create a new substance unlike physical substances .
A) 4400 kj of heat released into surroundings
<h3>Further explanation</h3>
Reaction
C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O, the ∆H is –2200 kJ
Reaction exothermic( ∆H=-, released heat to surrounding) and for combustion of 1 mole of C3H8
So for two moles of C3H8, the enthalpy :
