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Gemiola [76]
1 year ago
15

Hydrogen sulfide gas is reacted with dioxygen gas to produce gaseous sulfur dioxide and water. True or false?.

Chemistry
1 answer:
wel1 year ago
4 0

Hydrogen sulfide gas is reacted with dioxygen gas to produce gaseous sulfur dioxide and water. It is false.

When hydrogen sulfide gas reacts with dioxygen gas, it produces water and solid Sulphur and not gaseous sulfur. The chemical equation of the given substances is :

                   2H2S +  O2 → 2S + 2H20

It is a redox reaction as both Oxidation and reduction happens in it. Oxidation of hydrogen sulphur to sulphur happens and reductions of oxygen to water takes place.  

if you need to learn more about chemical reaction of Hydrogen sulfide gas, click here

brainly.com/question/15842521?referrer=searchResults

#SPJ4

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What is the hydronium ion concentration of a 0.100 M acetic acid solution with Ka = 1.8 × 10-5? The equation for the dissociatio
evablogger [386]

Answer:

1.3×10⁻³ M

Explanation:

Hello,

In this case, given the dissociation reaction of acetic acid:

CH_3CO_2H(aq) + H_2O(l) \rightleftharpoons H_3O^+(aq) + CH_3CO_2^-(aq)

We can write the law of mass action for it:

Ka=\frac{[H_3O^+][CH_3CO_2^-]}{[CH_3CO_2H]}

Of course, excluding the water as heterogeneous substances are not included. Then, in terms of the change x due to the dissociation extent, we are able to rewrite it as shown below:

1.8x10^{-5}=\frac{x*x}{0.100-x}

Thus, via the quadratic equation or solve, we obtain the following solutions:

x_1=-0.00135M\\x_2=0.00133M

Obviously, the solution is 0.00133M which match with the hydronium concentration, thus, answer is: 1.3×10⁻³ M in scientific notation.

Regards.

8 0
3 years ago
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A silver coin with a mass of 14.1g has a density of 10.5 grams
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Answer:

1.34 cubic centimeter

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5 0
3 years ago
In a 63.17 g sample of SO3, how many grams are sulfur?
Evgesh-ka [11]

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4 0
2 years ago
127) Thirty-six colonies grew in nutrient agar from 1.0 ml of undiluted sample in a standard plate count. How many cells were in
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Answer:

36

Explanation:

Since the sample was undiluted the number of colonies is the number that grew on the nutrient agar which is 36 colonies. If it was diluted for example let say 0.1 ml from a dilution in which 1 ml of the sample was added to 9 ml of water, and it grew  colonies then  0.1 ml  yielded  6 colonies, 1 ml of the diluted sample will yield 60 colonies and 10 ml will have 600 colonies and therefore the 1 ml undiluted sample will have 600 colonies.

6 0
3 years ago
What is the mass of 4.32 mol GaI3? <br> 455 g <br> 1,230 g <br> 1,720 g <br> 1,950 g
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D. 1,950 g

Explanation:

I completed the test and it is the correct answer!

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