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Calculate the molarity of a solution prepared by dissolving 0.2 mol sucrose in enough water to make a 100 ml solution.

Lelechka [254]

Taking into account the definition of molarity, the molarity of a solution prepared by dissolving 0.2 mol sucrose in enough water to make a 100 mL solution is 2 $\frac{moles}{liter}$ .

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

$molarity=\frac{number of moles}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$ .

<h3>Molarity in this case</h3>

In this case, you have:

number of moles= 0.2 moles
volume= 100 mL= 0.1 L

Replacing in the definition of molarity:

$molarity=\frac{0.2 mole}{0.1 L}$

Solving:

<u><em>molarity= 2 </em></u> $\frac{moles}{liter}$

Finally, the molarity of a solution prepared by dissolving 0.2 mol sucrose in enough water to make a 100 mL solution is 2 $\frac{moles}{liter}$ .

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8 0

2 years ago

What will determine the number of moles of hydronium in an aqueous solution of a strong monoprotic acid?.

marin [14]

Answer:

What will determine the number of moles of hydronium in an aqueous solution of a strong monoprotic acid? The amount of acid that was added.

Explanation:

3 0

2 years ago

HELLLLP ITS 8TH GRADE SCIENCE AND DUE TODAY

insens350 [35]

Answer:G

Explanation:

I would look it up on safari just to be sure tho, hope this helps

6 0

2 years ago

Could someone help me with this?

Varvara68 [4.7K]

Solving part-1 only

#1

KMnO_4

Transition metal is Manganese (Mn)

#2

Actually it's the oxidation number of Mn

Let's find how?

$\\ \tt\Rrightarrow x+1+4(-2)=0$

$\\ \tt\Rrightarrow x+1-8=0$

$\\ \tt\Rrightarrow x-7=0$

$\\ \tt\Rrightarrow x=+7$

x is the oxidation number

#3

Purple as per the color of potassium permanganate

#4

$\boxed{\begin{array}{c|c|c}\boxed{\bf Tube} &\boxed{\bf Charge} &\boxed{\bf No\:of\; electrons\: loss}\\ \sf 2 &\sf +6 &\sf 6e^-\\ \sf 3& \sf +2 &\sf 2e- \\ \sf 4 &\sf 4 &\sf 4e^-\end{array}}$

7 0

2 years ago

For the reaction PC15 (8) PC13 (g) + Cl2 (g) K = 0.0454 at 261 °C. If a vessel is filled with these gases such that the initial

Fiesta28 [93]

Answer:

The correct answer is B.

The $K_{eq}$ is samller than $Q$ of the reaction . So,the reaction will shift towards the left i.e. towards the reactant side.

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{eq}$

K is the constant of a certain reaction when it is in equilibrium, while Q is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

For the given chemical reaction:

$PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)$