Explanation:
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1 answer:
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Answer:
1-bromo-6-methylheptane : X
2-chloro-6-methylheptane: Y
Explanation:
A chiral compound is one which has a carbon with all four groups different.
Given:
Compound X is Achiral
Compound Y is chiral
Compound X gives single alkene on elimination : Z
Compound Y gives mixture of alkenes
Z on hydrogenation gives 2-methylheptane.
So the alkene must have carbon chain arrangement similar to 2-methylheptane and so the compound X and Y.
Based on the information the possible compounds are:
1-bromo-6-methylheptane : X
2-chloro-6-methylheptane: Y
The structures are shown in the figure.
Answer:
Periodo: 3.
Grupo: IIA.
Explanation:
Hola.
En este caso, es posible determinar el periodo y grupo por medio de la configuración electrónica del elemento que tiene 12 electrones:
De este modo, vemos que el termino final es , por lo tanto, decimos que el periodo es 3, ya que este coincide con el nivel de energía. Adicionalmente, para
tenemos que el átomo se encuentra en el grupo IIA ya que tiene dos electrones en su capa o nivel (3) más externa. Esto coincide con el número cuántico dado (magnético, ml=0) ya que cuando el término en la configuración electrónica tiene el subnivel
, este tiene un valor de cero.
Así, el elemento en cuestión sería Magnesio.
¡Saludos!
Answer:
Approximately (at STP.)
Assumption: both and
act like ideal gases.
Explanation:
Make sure that this chemical equation is properly balanced.
The ratio between the coefficient of and that of
is
. As a result, for every
of
consumed,
of
will be produced.
In other words:
.
The coefficients in the balanced equation give a relationship between the number of moles of the two species. One more step is required to obtain a relationship between the volume of these two species.
Under the same pressure and temperature, two ideal gases with the same number of gas particles will have the same volume. Additionally, the volume of an ideal gas is proportional to the number of particles in it.
In this question, if both and
are at STP, their pressure and temperature would indeed be the same. If they are both assumed to be ideal gases, then the ratio between their volumes would be the same as the ratio between the number of moles of their particles. that is:
.
Therefore, to produce of
, the minimum volume of
would be:
.