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zvonat [6]
3 years ago
11

The question is in the picture above ! help!

Chemistry
1 answer:
Crank3 years ago
7 0

Answer:

El pepe

Explanation:

ete sech xd uwu o ni chan

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Of these elements, which has the largest atomic radius?<br> Ar<br> S<br> Cl
VARVARA [1.3K]
The answer is CI because that is the largest
7 0
3 years ago
Which best describes the pH scale?
oksano4ka [1.4K]
The answer is B. bases measure below seven 
think of it like this 7 is neutral going down from seven it rises in acidity and going up from seven increases in alkalinity 
4 0
3 years ago
What is the highest energy orbital of elements with valence electrons in the n=3 shell?
Andrej [43]

Answer:

d orbital

Explanation:

Given that:-

The principal quantum number, n = 3

The acceptable values of azimuthal quantum number, l are:-

l = 0 , 1 , 2

l = 0 corresponds to s orbital which can accomodate 2 electrons.

l = 1 corresponds to p orbital which can accomodate 6 electrons.

l = 2 corresponds to d orbital which can accomodate 10 electrons.

<u>Thus, the highest energy orbital is: - d orbital</u>

8 0
4 years ago
How many protons does an atom of zinc contain?<br> It contains an amount
madreJ [45]

a single neutral atom of zinc has 30 protons

3 0
3 years ago
Calculate the volume in milliliters of a iron(II) bromide solution that contains of iron(II) bromide . Round your answer to sign
miv72 [106K]

This is an incomplete question, here is a complete question.

Calculate the volume in milliliters of a 1.29 mol/L iron(II) bromide solution that contains 275 mmol of iron(II) bromide . Round your answer to significant 3 digits.

Answer  : The volume of iron(II) bromide solution is, 2.13\times 10^2mL

Explanation : Given,

Concentration of iron(II) bromide = 1.29 mo/L

Moles of iron(II) bromide = 275 mmol = 0.275 mol

conversion used : 1 mmol = 0.001 mol

Now we have to calculate the volume of iron(II) bromide.

\text{Volume of iron(II) bromide}=\frac{Moles of iron(II) bromide}}{\text{Concentration of iron(II) bromide}}

Now put all the given values in this formula, we get:

\text{Volume of iron(II) bromide}=\frac{0.275mol}{1.29mol/L}=0.213L=2.13\times 10^2mL

Thus, the volume of iron(II) bromide solution is, 2.13\times 10^2mL

5 0
3 years ago
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