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marusya05 [52]
3 years ago
7

A student gets 68 marks n therefore gets 85 percent total marks are?

Mathematics
1 answer:
mihalych1998 [28]3 years ago
4 0

Answer:

There are 80 marks in total.

Step-by-step explanation:

Let the number of total marks be x.

The percentage score of the student can be written as the ratio

\displaystyle \frac{68}{x} = 85\%.

However,

\displaystyle 85\% = \frac{85}{100}.

Equating the two:

\displaystyle \frac{68}{x} = \frac{85}{100}.

Cross-multiply (that is: multiple both sides by 100x, the product of the two denominators) to get

85x = 68\times 100.

\displaystyle x = \frac{68\times 100}{85} = 80.

In other words, there are 80 marks in total.

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Answer:

z=2.53  

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Step-by-step explanation:

1) Data given and notation

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p_o=0.5 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that majority of adults​ (more than​ 50%) support a ban on sugary snacks and soft​ drinks, the system of hypothesis are:  

Null hypothesis:p\leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.54 -0.5}{\sqrt{\frac{0.5(1-0.5)}{1000}}}=2.53  

4) Statistical decision  

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The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a one side right tailed test the p value would be:  

p_v =P(z>2.53)=0.0057  

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