Question

Write an equation of a line in slope intercept form that is parallel to y = 3x+6 and passes through the point (-10, 2.5)

Answer 1

1) Line should be parallel to y = 3x+6, so slope of this line should be =3.

y=mx +b

y=3x +b

Now we have to find b (y-intercept), using the point (-10, 2.5).

2.5 = 3*(-10)+b

b=2.5+30=32.5

y=3x + 32.5

2) The line should be perpendicular to y = -4x -2, so its slope is going to be negative reciprocal m= 1/4.

Now we have to find b (y-intercept), using the point (-16, -11).

y=(1/4)x +b

-11=(1/4)*(-16) + b

-11 = -4 +b

b = -7

y=(1/4)x - 7