1. Cu + 2AgNO3 ==> 2Ag + Cu(NO3)2 ... balanced equation. This is both a single replacement reaction and an oxidation reduction reaction.
Moles of Cu present = 19.0 g Cu x 1 mole Cu/63.55 g = 0.2990 moles Cu
Moles AgNO3 = 125 g AgNO3 x 1 mole AgNO3/169.9 g = 0.7357 moles AgNO3
Which reactant is limiting? It will be Cu because the mole ratio is 2 AgNO3 to 1 Cu and there is more than enough AgNO3. Thus, amount of Ag formed will depend on moles of Cu (0.2990)
Moles of Ag formed = 0.2990 moles Cu x 2 moles Ag/mole Cu = 0.598 moles Ag
Mass (grams) of Ag formed = 0.598 moles Ag x 107.9 g/mole = 64.52 g = 64.5 g of Ag (3 sig. figs.)
S orbital can hold 2
P can hold 6
D can hold 10
F can hold 14
Basic facts about sex and reproduction, as told to a child
NaCl + H2O = HCl + NaOH
FIRST write the equation and balance the equation THEN convert the volume of the gas to moles of the gas PV=nRT THEN according to the stoichiometry of the reaction one mol of gas is produced by one mol of salt. Convert the mol of gas to mol of salt FINALLY calculate the molar mass of the salt and convert the mol of salt to g of salt (m= nxMM)
