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nydimaria [60]
3 years ago
9

Which of the following rocks would you most likely find in a cave? conglomerate foliated metamorphic rock chemical sedimentary r

ock intrusive igneous rock
Chemistry
2 answers:
docker41 [41]3 years ago
5 0

The correct answer is chemical sedimentary rock

These Chemical sedimentary rock are formed due to supersaturation of mineral constituent resulting in precipitation of them.

This is a kind of sedimentary rock which is most likely to be formed in a cave.

GenaCL600 [577]3 years ago
4 0
Chemical Sedimentary
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A chemical reaction produced 177.3 grams of chlorine has (Cl²). What was the volume of the gas?
vichka [17]
Since there is so little information given, I will assume that we are at STP and i can use the conversion factor at STP--->> 22.4 Liters= 1 mol of gas

before we use this conversion, we need to convert the grams to moles using the molar mass of the molecule.

molar mass of Cl₂= 35.5 x 2= 71.0 g/ mol

177.3 g (1 mol/ 71.0 g)= 2.50 mol Cl₂

then we use the conversion to get the volume

2.50 mol Cl₂ (22.4 Liters/ 1 mol)= 55.9 Liters
3 0
3 years ago
The equation below represents a double replacement/displacement reaction;
Naddik [55]
AB+XY->AY+XB
We know that the answer would be KCl because of the switching that takes place during a double displacement reaction. Just like Zn and MnO4 switched and combined, the remaining elements, K and Cl, will combine.
We know that the answer is simply KCl because both K and Cl have an ion of only +/-1, meaning when they cross, no suffixes are made, since their ions are only 1.
For example, if you combined Mg with Cl, you would get MgCl2, because Mg has an ion of +2.
I hope this helps!
4 0
3 years ago
Balance the equations.<br> Zn+ HCl →<br> ZnCl2 +
motikmotik

Answer:

Zn + 2HCl → ZnCl2 + H2

Explanation:

Zn + HCl → ZnCl2 +

The complete equation is given below:

Zn+ HCl → ZnCl2 + H2

Now we can balance the equation by doing the following:

There are 2 atoms of Cl and 2 atoms of H on the left. This can be balanced by putting 2 in front of HCl as shown below:

Zn + 2HCl → ZnCl2 + H2

7 0
3 years ago
Aluminum reacts with sulfur gas to produce aluminum sulfide. a) What is the limiting reactant? What is the excess reagent? b) Ho
Sophie [7]

Answer:

a) Limiting: sulfur. Excess: aluminium.

b) 1.56g Al₂S₃.

c) 0.72g Al

Explanation:

Hello,

In this case, the initial mass of both aluminium and sulfur are missing, therefore, one could assume they are 1.00 g for each one. Thus, by considering the undergoing chemical reaction turns out:

2Al(s)+3S_2(g)\rightarrow 2Al_2S_3(s)\\

a) Thus, considering the assumed mass (which could be changed based on the one you are given), the limiting reagent is identified as shown below:

n_S^{available}=1.00gS_2*\frac{1molS_2}{64gS_2} =0.0156molS_2\\n_S^{consumed\ by \ Al}=1.00gAl*\frac{1molAl}{27gAl}*\frac{3molS_2}{2molAl}=0.0556molS_2

Thereby, since there 1.00g of aluminium will consume 0.0554 mol of sulfur but there are just 0.0156 mol available, the limiting reagent is sulfur and the excess reagent is aluminium.

b) By stoichiometry, the produced grams of aluminium sulfide are:

m_{Al_2S_3}=0.0156molS_2*\frac{2molAl_2S_3}{3molS_2} *\frac{150gAl_2S_3}{1molAl_2S_3} =1.56gAl_2S_3

c) The leftover is computed as follows:

m_{Al}^{excess}=(0.0556-0.0156)molS_2*\frac{2molAl}{3molS_2}*\frac{27gAl}{1molAl} =0.72 gAl\\

NOTE: Remember I assumed the quantities, they could change based on those you are given, so the results might be different, but the procedure is quite the same.

Best regards.

7 0
2 years ago
The inputs for cellular respiration are
katrin [286]
Glycolysis--The breakdown of a glucose molecule into two three-carbon pieces called pyruvate. You will notice that very little ATP is produced in this step and no oxygen is required. ... This step is also where other molecules besides glucose may be fed into the cell respiration<span> process, especially lipids.</span>
5 0
3 years ago
Read 2 more answers
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